Approximate molecular masses:
Molecular mass of C = 12
Molecular mass of H = 1
Let n = moles required for CH₂.
Then
nCH₂ = 98
n(12 + 2*1) = 98
14n = 98
n = 7
Answer: The molecular formula is 7CH₂
Answer:
1/3
Explanation:
Pyruvate is produced by the glycolysis in cytoplasm. The oxidation of pyruvate takes place in mitochondrial matrix.
Pyruvate is converted to acetyl-CoA in the reaction given below:
Pyruvate + NAD⁺ + CoA-SH ⇒ acetyl-CoA + NADH + CO₂
1 molecule of carbon dioxide is eliminated from 1 molecule of pyruvate.
Also,
2 molecules of carbon dioxide is eliminated from 2 molecules of pyruvate (as glucose on glycolysis yields 2 molecules of pyruvate).
Also, acetyl-CoA further goes into the citric acid cycle and produces 2 molecules of carbon dioxide.
Thus pyruvate produces total 3 molecules of CO₂ and hence glucose produces 6 molecules of CO₂ (as glucose on glycolysis yields 2 molecules of pyruvate)
Thus,
<u>Fraction = 2/6 = 1/3</u>
1-Electric Energy
Example: A lightbulb is an example of electric energy
2-Sound Energy
Example: When a dog barks, that is sound energy
3-Solar Energy
Example: When we use the sun for energy. Like using it to dry our clothes.
4-Chemical Energy
Example: An example is a battery. That may not seem like it, but it is Chemical Energy.
5-Nuclear Energy
Example: A fission reaction at a nuclear powerplant
6-Thermal Energy
Example: A pot of water boiling on an Electric Stove
~Silver
Answer:
<h2>mass = 10.72 g</h2>
Explanation:
Density of a substance can be found by using the formula
Making mass the subject we have
From the question
Density = 2.70 g/cm³
We assume that the aluminum is a cuboid
and volume of a cuboid is given by
Volume = length × width × height
length = 5.3 cm
width = 0.32 cm
height = 2.34 cm
Volume = 5.3 × 0.32 × 2.34 = 3.97 cm³
Substitute the values into the above and solve for the mass
We have
mass = 2.70 × 3.97
We have the final answer as
<h3>mass = 10.72 g</h3>
Hope this helps you
<span>2NaCN + (1)H2SO4 → Na2SO4 + 2HCN
</span><span>The coefficient of sulfuric acid is 1.</span>
