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3 years ago

What is the value of x in this equation [x+17]=20x

Mathematics

1 answer:

Digiron [165]3 years ago

3 0

Answer:

0.90=X or 0.89=X

If it's not right, then i'm sorry :)

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Can somebody please help me

Ksenya-84 [330]

Answer:

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Step-by-step explanation:

8 0

3 years ago

(8-5/2-2)-4<br> =?<br><br> Please helping me!!!

frez [133]

Answer: Hope This Helps!

Step-by-step explanation:

Simplify the expression.

Exact Form:

87/40

Decimal Form:

2.175

Mixed Number Form:

2 7/40

5 0

2 years ago

If f(n) = -6n + 2, find f (5/6)

joja [24]

$f( \frac{5}{6} ) = - 6( \frac{5}{6} ) + 2 \\ f( \frac{5}{6} ) = - \frac{30}{6} + 2 \\ f( \frac{5}{6} ) = - 5 + 2 \\ f( \frac{5}{6} ) = - 3$

7 0

3 years ago

Read 2 more answers

Stacy started a banking account with $150 and is spending $7 per day on lunch. This situation models which type of function?

Lubov Fominskaja [6]

Answer:

Linear

Step-by-step explanation:

She is spending the same amount per day, so it is linear

8 0

3 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago