9)
8x+4*6
8x+24
11)
3t+2c=6tc
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Um... I think you meant <span>24:96 = 5:x
In that case, x=20
</span>
Answer:
sixty-two plus 7 times a number h
Step-by-step explanation:
Find the area of the room by multiplying the length by the width:
Area of room = 20 x 12 = 240 square feet.
Find the area of the tile: 2x 2 = 4 square feet.
To find the number of tiles divide the area of the room by the area of a tile:
240/4 = 60
They will need 60 tiles.
