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3 years ago

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What is the net force acting on a 52 kg object that has a velocity of 8.0 m/s and is moving in a circle of radius 1.6 m? a. 4000

N b. 20880N c. 2500N d. 3500N

1 answer:

jenyasd209 [6]3 years ago

7 0

Σf = m a
Σf = m v^2 / r
Σf = 52 8^2 / 1.6
Σf = 2080 N

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