Answer:
A. when the mass has a displacement of zero
Explanation:
The velocity of a mass on a spring can be calculated by using the law of conservation of energy. In fact, the total energy of the mass-spring system is equal to the sum of the elastic potential energy (U) of the spring and the kinetic energy (K) of the mass:

where
k is the spring constant
x is the displacement of the mass with respect to the equilibrium position of the spring
m is the mass
v is the velocity of the mass
Since the total energy E must remain constant, we can notice the following:
- When the displacement is zero (x=0), the velocity must be maximum, because U=0 so K is maximum
- When the displacement is maximum, the velocity must be minimum (zero), because U is maximum and K=0
Based on these observations, we can conclude that the velocity of the mass is at its maximum value when the displacement is zero, so the correct option is A.
A horseshoe magnet has north and south, so does a bar magnet, but with the horseshoe magnet, the whole thing is bent so both ends are the same way. <span />
Vo = 89 m/s
angle: 40°
=> Vox = Vo * cos 40° = 89 * cos 40°
=> Voy = Vo. sin 40° = 89 * sin 40°
x-movement: uniform => x =Vox * t = 89*cos(40)*t
x = 300 m => t = 300m / [89m/s*cos(40) = 4.4 s
y-movement: uniformly accelerated => y = Voy * t - g*t^2 /2
y = 89m/s * sin(40) * (4.4s) - 9.m/s^2 * (4.4)^2 / 2 = 156.9 m = height the ball hits the wall.
Well one is from potential energy to ascensive moving energy . And another is from electrical to circuit energy.