The info below shows three kettles with their powers and the time they take to boil 500cm3 of water. If electricity costs 9p per
1 answer:
You might be interested in
Answer:
6 teaspoons of baking powder required.
Explanation:
Given that
According to the recipe of pancake,
For every teaspoon of salt, 2 teaspoons of baking baking powder is required.
To find:
How much baking powder will be needed, if 1 teaspoon of salt was used ?
Solution:
This problem can be solved using ratio.
teaspoon of salt : 2 teaspoons of baking powder
Let us multiply the above ratio with 3.
teaspoon of salt : 2
3 teaspoons of baking powder
OR
1 teaspoon of salt : 6 teaspoons of baking powder
So, answer is <em>6 teaspoons </em>of baking powder required.
Also, we can use the unitary method:
teaspoon of salt needs = 2 teaspoons of baking powder
1 teaspoon of salt needs = teaspoons of baking powder
1 teaspoon of salt needs = 2 3 = <em>6</em> teaspoons of baking powder needed
So, the answer is:
<em>6 teaspoons of baking powder </em>required.
The kinematic relationships we can find the position, acceleration and launch angle of the body on the planet Exidor.
a) the position are
time (s) x (m) y(m)
0 0 0
2.0 3.6 1.2
3.0 5.4 0.9
b) The aceleration is g = 0.6 m / s²
c) The launch angle θ = 33.7º
given parameters
- the initial velocity of the body vₓ = 1.8m / s and v_y = 1.2 m / s
- the movement times t = 1.0s, 2.0s and 3.0 s
to find
a) position
b) acceleration
c) launch angle
Projectile launch is an application of kinematics to the movement of the body in two dimensions where there is no acceleration on the x axis and the y axis has the planet's gravity acceleration
b) To calculate the acceleration of the plant acting on the y-axis, we use that the vertical velocity of the body at the highest point is zero.
v_y = v_{oy} - g t
where v and v({oy} are the velocities of the body, g the acceleration of the planet's gravity and t the time
0 = v_{oy} - gt
g = v_{oy} / t
from the graph we observe that the highest point occurs for t = 2.0 s
g = 1.2 / 2.0
g = 0.6 m / s²
a) The position is requested for several times
X axis
in this axis there is no acceleration so we can use the uniform motion relationships
vₓ = x / t
x = vₓ t
where x is the position, vx is the velocity and t is the time
we calculate for the time
t = 0.0 s
x₀ = 0
t = 2.0 s
x₂ = 1.8 2
x₂ = 3.6 m
t = 3.0 s
x₃ = 1.8 3
x₃ = 5.4 m
Y axis
In this axis there is the acceleration of the planet, let us use for the position the relation
y = v_{oy} t - ½ g t²
t = 0.0 s
y₀ = 0
y₀ = 0 m
t = 2.0 s
y₂ = 1.2 2 - ½ 0.6 2²
y₂ = 1.2 m
t = 3.0 s
y₃ = 1.2 3 - ½ 0.6 3²
y₃ = 0.9 m
c) the launch angle use the trigonometry relation
tan θ =
θ = tan⁻¹
θ = tan⁻¹
θ = 33.7º
measured counterclockwise from the positive side of the x-axis
With the kinematic relationships we can find the position, acceleration and launch angle of the body on the planet Exidor.
a) the position are
time (s) x (m) y(m)
0 0 0
2.0 3.6 1.2
3.0 5.4 0.9
b) The aceleration is g = 0.6 m / s²
c) The launch angle θ = 33.7ºto)
learn more about projectile launch here: