Question

The info below shows three kettles with their powers and the time they take to boil 500cm3 of water. If electricity costs 9p per unit, how much does it cost to boil 500cm3 of water using the 3kW kettle?
Kettle 1= 3mins =3kW
Kettle 2= 3.5mins= 2.2kW
Kettle 3=4.5mins=1.4kW

Answer 1

The cost of boiling 500 cm³ of water using the 3 KW Kettle is 1.35p

What is power?

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = Energy (E) / time (t)

P = E / t

How to determine the energy

• Power (P) = 3 KW
• Time (t) = 3 mins = 3 / 60 = 0.05 h
• Energy (E) =?

E = Pt

E = 3 × 0.05

E = 0.15 KWh

How to determine the cost

• Energy (E) = 0.15 KWh
• Cost per unit = 9p
• Cost =?

Cost = Energy × cost per unit

Cost = 0.15 × 9

Cost = 1.35p

Learn more about electrical power:

brainly.com/question/64224

#SPJ1