Answer:
an animal that transfers pollen from flower to flower
Explanation:
think of a bee, bees move from flowers to flowers dropping pollen places and then it helps the plants grow.
Answer:
True
It is true that he size of coupling constants (J values) depend on three factors:
a. Through bond distance between the protons.
b. Angle between the two C-H bonds.
c. Electronegative substituents.
Explanation:
With the increase in the valence angle the coupling constant reduces. The distance between the carbon atoms also influence coupling constant. With increase in bond length, the coupling constant decreases. Also the more an atom is electronegative, the lesser is the coupling constant
Thus, it is true that he size of coupling constants (J values) depend on three factors:
a. Through bond distance between the protons.
b. Angle between the two C-H bonds.
c. Electronegative substituents.
Completed Question:
The decomposition of sulfuryl chloride, SO2Cl2, to sulfur dioxide and chlorine gases is a first order reaction. IT is found taht it takes 13.7 hours to decompose a 0.250 M SO2Cl2 solution to 0.117 M. What is the rate constant for the decomposition?
Answer:
0.04 h⁻¹
Explanation:
If the decomposition occurs at a first-order reaction, it means that the rate of the reaction can be expressed as:
rate = k*[SO2Cl2]
Where k is the rate constant, and [SO2Cl2] is the initial concentration of SO2Cl2. The rate is also the variation of the concentration by the time, so it is:
rate = (0.250 - 0.117)/13.7
rate = 0.0098 M/h
Thus, the concnetration decays 0.0098 M for each hour. The rate constant is then:
0.0098 = k*0.250
k = 0.04 h⁻¹
Answer:
1632 Hz
Explanation:
We'll begin by calculating the frequency of each wave. This can be obtained as follow:
1st wave:
Velocity (v) = 340 m/s.
Wavelength 1 (λ₁) = 5 m
Frequency 1 (f₁) =?
v = λ₁f₁
340 = 5 × f₁
Divide both side by 5
f₁ = 340 / 5
f₁ = 68 Hz
2nd wave:
Velocity (v) = 340 m/s.
Wavelength 2 (λ₂) = 0.2 m
Frequency 2 (f₂) =?
v = λ₂f₂
340 = 0.2 × f₂
Divide both side by 0.2
f₂ = 340 / 0.2
f₂ = 1700 Hz
Finally, we shall determine the difference in the frequency of both waves.
This can be obtained as follow:
Frequency 1 (f₁) = 68 Hz
Frequency 2 (f₂) = 1700 Hz
Difference =?
Difference = f₂ – f₁
Difference = 1700 – 68
Difference = 1632 Hz
Answer:
Ea = 210.5kJ/mole
Explanation:
When the reaction:
O3 + NO → O2 + NO2
Occurs, requires 10.7kJ/mole and releases -199.8kJ/mole.
For the forward reaction:
O2 + NO2 → O3 + NO
The Ea is the sum of Ea of the forward reaction and - ΔH, that is:
Ea = Ea - (-ΔH)
Ea = 10.7kJ/mol - (-199.8kJ/mol)
Ea = 210.5kJ/mole
