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Gwar [14]
3 years ago
10

The work function of an element is the energy required to remove an electron from the surface of the solid. The work function fo

r palladium is 503.7 kJ/mol (that is, it takes 503.7 kJ of energy to remove 1 mole of electrons from 1 mole of Pd atoms on the surface of Pd metal). What is the maximum wavelength of light that can remove an electron from an atom in palladium metal
Chemistry
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

λ = 2.38 × 10^(-7) m

Explanation:

We are given the work function for palladium as 503.7 kJ/mol.

Now let's convert this to KJ/electron.

We know from avogadro's number that;

1 mole of electron = 6.022 × 10^(23) electrons

Thus,

503.7 kJ/mol = 503.7 × 1/(6.022 × 10^(23)) = 8.364 × 10^(-22) KJ/electron = 8.364 × 10^(-19) J/electron

Formula for energy of a photon is;

E = hv

Where;

h is Planck's constant = 6.626 × 10^(-34) J.s

v is velocity

Now, v = c/λ

Where;

c is speed of light = 3 × 10^(8) m/s

λ is wavelength of light.

Thus;

E = hc/λ

Making λ the subject, we have;

λ = hc/E

λ = (6.626 × 10^(-34) × 3 × 10^(8))/(8.364 × 10^(-19))

λ = 2.38 × 10^(-7) m

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barxatty [35]

Answer:

No more than 0.1 mL of hydrochloricton acid

5 0
3 years ago
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Zielflug [23.3K]
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3 years ago
How many grams of NaCl are in 3.5 mol of NaCl? Also, how many moles of NaCl are in 150 g of NaCl?​
alexandr402 [8]

Answer:

204.5505 grams

2.5666 moles

Explanation:

For the first question, multiply 3.5 (# of moles) by 58.443 (g/mol for NaCl).

58.443 * 3.5

<em>I'll distribute 3.5 into 58.443.</em>

(3.5 * 50) + (3.5 * 8) + (3.5 * 0.4) + (3.5 * 0.04) + (3.5 * 0.003)

175 + 28 + 1.4 + 0.14 + 0.0105

203 + 1.4 + 0.14 + 0.0105

204.4 + 0.14 + 0.0105

204.54 + 0.0105

204.5505 grams

There are 204.5505 grams in 3.5 moles of NaCl.

For the second question, divide 150 (# of grams) by 58.443 (g/mol for NaCl). I'll convert both into fractions.

150/1 * 1000/58443

150000/58443

2.56660336 moles

2.5666 moles (rounded to 4 places to keep consistency with the first answer) are in 150 grams of NaCl.

6 0
3 years ago
The enthalpy of solution (dissolving) of sodium hydroxide is given below. Determine the change in temperature of a coffee cup ca
geniusboy [140]

Answer:

The change in temperature of a coffee cup calorimeter is 8.87°C.

Explanation:

Volume of the water = V = 150 g

Density of the water , d =1.0 g/mL

Mass of the water = M

M=d\times V=1.00 g/mL\times 150 ml =150.0 g

Mass of solution = m = M = 150.0 g

NaOH(s)\rightarrow NaOH(aq),\Delta H =-44.51 kJ/mol

Moles of NaOH = \frac{5.00 g}{40 g/mol}=0.125 mol

Energy released when 0.125 moles of NaOH added in water = Q

Q=0.125 moles\times (-44.51 kJ/mol)=-5.5638 kJ=-5,563.8 J

1 kJ = 1000 J

Heat gained by water = Q' = -Q ( conservation of energy)

Q'= 5,563.8 J

Specific heat of solution = c = 4.184 J/g°C

Change in temperature of the solution = \Delta T

Q'=mc\times \Delta T

5,563.8 J=150.0 g\times 4.184 J/g^oC\times \Delta T

\Delta T=\frac{5,563.8 J}{150.0 g\times 4.184 J/g^oC}=8.87^oC

The change in temperature of a coffee cup calorimeter is 8.87°C.

7 0
3 years ago
Mg + 2 AgNO₃ → Mg(NO₃)₂ + 2 Ag How many grams of magnesium nitrate, Mg(NO₃)₂, are formed when 9.87 moles of silver nitrate, AgNO
Aleksandr-060686 [28]

Mass of Magnesium nitrate formed : 731.86 g

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

Mg + 2AgNO₃ → Mg(NO₃)₂ + 2 Ag

moles of silver nitrate, AgNO₃ = 9.87

mole ratio AgNO₃ : Mg(NO₃)₂ = 2 : 1, so mol Mg(NO₃)₂ :

\tt \dfrac{1}{2}\times 9.87=4.935

mass of Mg(NO₃)₂(MW=148,3 g/mol) :

\tt mass=mol\times MW\\\\mass=4.935\times 148,3\\\\mass=731.86~g

4 0
3 years ago
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