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Gwar [14]
2 years ago
10

The work function of an element is the energy required to remove an electron from the surface of the solid. The work function fo

r palladium is 503.7 kJ/mol (that is, it takes 503.7 kJ of energy to remove 1 mole of electrons from 1 mole of Pd atoms on the surface of Pd metal). What is the maximum wavelength of light that can remove an electron from an atom in palladium metal
Chemistry
1 answer:
uranmaximum [27]2 years ago
4 0

Answer:

λ = 2.38 × 10^(-7) m

Explanation:

We are given the work function for palladium as 503.7 kJ/mol.

Now let's convert this to KJ/electron.

We know from avogadro's number that;

1 mole of electron = 6.022 × 10^(23) electrons

Thus,

503.7 kJ/mol = 503.7 × 1/(6.022 × 10^(23)) = 8.364 × 10^(-22) KJ/electron = 8.364 × 10^(-19) J/electron

Formula for energy of a photon is;

E = hv

Where;

h is Planck's constant = 6.626 × 10^(-34) J.s

v is velocity

Now, v = c/λ

Where;

c is speed of light = 3 × 10^(8) m/s

λ is wavelength of light.

Thus;

E = hc/λ

Making λ the subject, we have;

λ = hc/E

λ = (6.626 × 10^(-34) × 3 × 10^(8))/(8.364 × 10^(-19))

λ = 2.38 × 10^(-7) m

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If i have 8 L of 0.25 M solution, how many miles of MgCl2 are present
qaws [65]

Answer:

2 moles

Explanation:

The following were obtained from the question:

Molarity = 0.25 M

Volume = 8L

Mole =?

Molarity is simply defined as the mole of solute per unit litre of solution. It is represented mathematically as:

Molarity = mole of solute/Volume of solution.

With the above equation, we can easily find the number of mole of MgCl2 present in 8 L of 0.25 M MgCl2 solution as follow:

Molarity = mole of solute/Volume of solution.

0.25 = mole of MgCl2 /8

Cross multiply to express in linear form

Mole of MgCl2 = 0.25 x 8

Mole of MgCl2 = 2 moles

Therefore, 2 moles of MgCl2 are present in 8 L of 0.25 M MgCl2 solution

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3 years ago
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Which is the correct terrm that indicated that an oceanic crust is pushed downward by a colliding contintental crust?
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What type of radiation is most likely to damage DNA?<br> A. ionizing<br> B. non-ionizing
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Explanation:

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Calculate to three significant digits the density of chlorine pentafluoride gas at exactly and exactly . You can assume chlorine
slega [8]

Answer:

Density is 6.16g/L

Explanation:

<em>... at exactly -15°C and exactly 1atm...</em>

<em />

Using general gas law:

PV = nRT

We can find density (Ratio of mass and volume) in an ideal gas as follows:

P/RT = n/V

<em>To convert moles to grams we need to multiply the moles with Molar Weight, MW:</em>

n*MW = m

n = m/MW

P/RT = m/V*MW

P*MW/RT = m/V

<em>Where P is pressure: 1atm;</em>

<em>MW of chlorine pentafluoride: 130.445g/mol</em>

<em>R is gas constant: 0.082atmL/molK</em>

<em>And T is absolute temperature: -15°C+273.15 = 258.15K</em>

<em />

Replacing:

P*MW/RT = m/V

1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V

6.16g/L = m/V

<h3>Density of the gas is 6.16g/L</h3>

<em> </em>

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