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777dan777 [17]
3 years ago
15

Which substance has the most thermal energy and will have the most heat flow from it?

Physics
2 answers:
Nata [24]3 years ago
6 0

Internal thermal energy will depends upon its temperature

so here the temperature range will be maximum 1000 degree C

so here maximum thermal energy is given by

<em>A Nuclear Reactor Core</em>

So here the maximum thermal energy and have the most heat flow is given by nuclear reactor core as it has maximum temperature

alisha [4.7K]3 years ago
5 0

Answer:

a nuclear reactor core (1000°C)

Explanation:

Thermal energy is the term used to describe the energy emitted by an object which atoms are moving at a certain rate due to the temperature, and or are rising its temperature, so thermal energy is closely related to the temperature of the objects, in this case the nuclear reactor core would be the one that has the most thermal energy since it has the highest temperature.

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A uniform electric field is created by two parallel plates separated by a distance of 0.04 m. What is the magnitude of the elect
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Complete question:

A uniform electric field is created by two parallel plates separated by a

distance of 0.04 m. What is the magnitude of the electric field established

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Answer:

The magnitude of the electric field established between the plates is 2,000 V/m

Explanation:

Given;

distance between two parallel plates, d = 0.04 m

potential between first and second plate, = +40V and -40V respectively

The magnitude of the electric field established between the plates is calculated as;

E = ΔV / d

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ΔV is change in potential between two parallel plates;

d is the distance between the plates

ΔV = V₁ -V₂

ΔV = 40 - (-40)

ΔV = 40 + 40

ΔV = 80 V

E = ΔV / d

E = 80 / 0.04

E = 2,000 V/m

Therefore, the magnitude of the electric field established between the plates is 2,000 V/m

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The given parameters:

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T = \frac{x}{V} \\\\T = \frac{x}{xH_0} \\\\T = \frac{1}{H_0} \\\\T = \frac{1}{70 \ km/s/Mpc} \\\\T = \frac{1 \ sec}{70 \times 3.24 \times 10^{-20} } \\\\T = 4.41 \times 10^{17} \ sec\\\\T = \frac{4.41 \times 10^{17} \ sec\  \times \ years}{3600 \ s \ \times\  24\ h\  \times \ 365.25 \ days} \\\\T = 1.397  \times 10^{10} \ years\\\\T = 13.97 \ billion \ years

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