1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phantasy [73]
4 years ago
15

On a highway, a car is driven 80. kilometers

Physics
2 answers:
nydimaria [60]4 years ago
7 0

The average speed of the car for the entire trip can be calculate by using:

v=\frac{S}{t}

where S is the total distance covered by the car, and t is the total time taken.


The total distance travelled by the car is:

S=80 km+50 km+40 km=170 km

while the total time taken is:

t=1.00 h+0.50 h+0.50 h=2.00 h


so, the average speed of the car is:

v=\frac{S}{t}=\frac{170 km}{2.00 h}=85 km/h


so, the correct answer is (3) 85 km/h.

Bas_tet [7]4 years ago
4 0

The average speed of the car for entire trip is \boxed{85\text{ km/h}}.

Further Explanation:

Speed is the measure of a quantity of an object the tells how fast the object is moving in the other words we can define the speed that it is the distance covered by an body divided by the time taken to cover that distance. It is a quantity with only magnitude so it is a scalar quantity.

The average speed is defined as the sum of all the distance traveled by the body divided by the sum of time taken to travel that distance.

Given:

The distance travel by the car is 80\text{ km} for 1.00\text{ hours}.

The distance travel by the car is 50\text{ km} for 0.50\text{ hours}.

The distance travel by the car is 40\text{ km} for .

0.50\text{ hours}.

Concept:

The expression for the average can be written as:

S =\dfrac{{{\text{sum of distances }}}}{{{\text{sum of time}}}}    …… (1)

The distance travel by the car is 80\text{ km} for 1.00\text{ hours}, distance travel by the car is 50\text{ km} for 0.50\text{ hours} and distance travel by the car is 40\text{ km} for 0.50\text{ hours}.

The sum of the distance is:

\begin{aligned}D&=80{\text{ km}}+{\text{50 km}}+40{\text{ km}}\\&=170{\text{ km}}\end{aligned}

The sum of time taken to travel the distance is:

\begin{aligned}t&=1.00{\text{ h}} + 0.50{\text{ h}} + 0.50{\text{ h}}\\&=2.00{\text{ h}}\end{aligned}

Substitute 170\text{ km} for total distance and 2.00\text{ h} for total time in equation (1).

\begin{aligned}S&=\frac{{{\text{170 km}}}}{{2.00{\text{ h}}}}\\&=85{\text{ km/h}}\end{aligned}

Therefore, the average speed of the car for entire trip is \boxed{85\text{ km/h}}.

Learn more:

1. Find the net force. https://brainly.in/question/8668644

2. Find the velocity. https://brainly.in/question/4502003

3. Calculate average speed brainly.com/question/11597590

Answer Details:

Grade: Middle school

Subject: Physics

Chapter: Kinematics

Keywords:

Highway, car, driven, 80 km, 1.00 hour, 1.00 hr, 1.00 h, 50 km, 0.50 hour, 0.50 hr, 0.50 h, 50  km, average speed, entire, trip, 85 km/hr.

You might be interested in
Which matter exists in the gaseous state at room temperature?
gulaghasi [49]
I would say (c.oxygen)
6 0
4 years ago
What is the mass of a ball being rolled with a force of 200N at 3.5 m/s2?
aalyn [17]
F=ma (c) Newton, 2d Law
m=F/a=200/3.5=57kg
6 0
3 years ago
Scientists are working on a new technique to kill cancer cells by zapping them with ultrahigh-energy (in the range of 1012 W) pu
Tcecarenko [31]

1. 7.95\cdot 10^6 J

The total energy given to the cells during one pulse is given by:

E=Pt

where

P is the average power of the pulse

t is the duration of the pulse

In this problem,

P=1.59\cdot 10^{12}W

t=5.0 ns = 5.0\cdot 10^{-9} s

Substituting,

E=(1.59\cdot 10^{12}W)(5.0 \cdot 10^{-6}s)=7.95\cdot 10^6 J

2. 1.26\cdot 10^{21}W/m^2

The energy found at point (1) is the energy delivered to 100 cells. The radius of each cell is

r=\frac{4.0\mu m}{2}=2.0 \mu m = 2.0\cdot 10^{-6}m

So the area of each cell is

A=\pi r^2 = \pi (2.0 \cdot 10^{-6}m)^2=1.26\cdot 10^{-11} m^2

The energy is spread over 100 cells, so the total area of the cells is

A=100 (1.26\cdot 10^{-11} m^2)=1.26\cdot 10^{-9} m^2

And so the intensity delivered is

I=\frac{P}{A}=\frac{1.59\cdot 10^{12}W}{1.26\cdot 10^{-9} m^2}=1.26\cdot 10^{21}W/m^2

3. 9.74\cdot 10^{11} V/m

The average intensity of an electromagnetic wave is related to the maximum value of the electric field by

I=\frac{1}{2}c\epsilon_0 E^2

where

c is the speed of light

\epsilon_0 is the vacuum permittivity

E is the amplitude of the electric field

Solving the formula for E, we find:

E=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(1.26\cdot 10^{21} W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12}F/m)}}=9.74\cdot 10^{11} V/m

4. 3247 T

The magnetic field amplitude is related to the electric field amplitude by

E=cB

where

E is the electric field amplitude

c is the speed of light

B is the magnetic field

Solving the equation for B and substituting the value of E that we found at point 3, we find

B=\frac{E}{c}=\frac{9.74\cdot 10^{11} V/m}{3\cdot 10^8 m/s}=3247 T

3 0
3 years ago
5. A 5.5 x10-6 C charge is located 0.28 m from a -3.5 x 10-6 C charge.
ra1l [238]

(a) The magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.

(b) If the negative charge is doubled, then the force will also get doubled.

The new force will be F = -4.418 N.

Explanation:

The force acting between two charged particles separated by a distance is termed as Coloumb's force or electrostatic force. It can be termed as electrostatic force of attraction if the the force acting between the charges are oppositely charged. And it can be termed as electrostatic force of repulsion if the charges are similar or like charges.

In the present case, there is a positive and negative charge, so electrostatic force of attraction will be acting between them. As per Coloumb's law, the electrostatic force of attraction is directly proportional to the product of charges and inversely proportional to the square of distance of separation.

F = \frac{kQq}{d^{2} }

Here, k is the constant of proportionality which is equal to 9 ×10^{9} and Q, q are the two charges, d is the distance of separation.

So here Q = 5.5 ×10^{-6} C and q = - 3.5 ×10^{-6} C and d = 0.28 m

Then, F=-\frac{9*10^{9}*5.5*10^{-6} * 3.5 * 10^{-6}  }{(0.28)^{2} } = 2209.82*10^{-3}

So the magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.

(b) If the negative charge is doubled, then the force will also get doubled.

The new force will be F = -4.418 N.

3 0
4 years ago
In first equation of motion at denotes​
RideAnS [48]

Answer:

Names of the Equations of Motion

1 The First Equation of Motion is, v=u+at is known as velocity – time relation. 2 The Second Equation of Motion is, s=ut+12at2 is known as position – time relation.

6 0
3 years ago
Other questions:
  • The change in pitch of a train's horn as it passes while you are standing still can be explained by
    11·1 answer
  • Which formula can be used to calculate the horizontal displacement not of a horizontally launched projectile
    10·1 answer
  • If the length of a ramp (an inclined plane) is 20ft, and it rises 5ft, what is its MA? (APEX)
    7·2 answers
  • What is the pathway of air into the body
    14·2 answers
  • Determine the voltage of source v2 in order for a 50a current to be delivered to the 0.5 ohm load resistor.
    14·1 answer
  • 9. During an egg toss, a catcher must cushion the egg by maximizing the time it takes to stop the
    7·1 answer
  • A tennis ball hits with an initial velocity of 25 m/s [10 o above the
    9·1 answer
  • While a roofer is working on a roof that slants at 36.0 ° above the horizontal, he accidentally nudges his 86 0 N toolbox, caus
    6·1 answer
  • How are the layers of the earth connected and affected by each other
    5·1 answer
  • What is the monthly (30 days) energy cost (in
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!