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Phantasy [73]
3 years ago
15

On a highway, a car is driven 80. kilometers

Physics
2 answers:
nydimaria [60]3 years ago
7 0

The average speed of the car for the entire trip can be calculate by using:

v=\frac{S}{t}

where S is the total distance covered by the car, and t is the total time taken.


The total distance travelled by the car is:

S=80 km+50 km+40 km=170 km

while the total time taken is:

t=1.00 h+0.50 h+0.50 h=2.00 h


so, the average speed of the car is:

v=\frac{S}{t}=\frac{170 km}{2.00 h}=85 km/h


so, the correct answer is (3) 85 km/h.

Bas_tet [7]3 years ago
4 0

The average speed of the car for entire trip is \boxed{85\text{ km/h}}.

Further Explanation:

Speed is the measure of a quantity of an object the tells how fast the object is moving in the other words we can define the speed that it is the distance covered by an body divided by the time taken to cover that distance. It is a quantity with only magnitude so it is a scalar quantity.

The average speed is defined as the sum of all the distance traveled by the body divided by the sum of time taken to travel that distance.

Given:

The distance travel by the car is 80\text{ km} for 1.00\text{ hours}.

The distance travel by the car is 50\text{ km} for 0.50\text{ hours}.

The distance travel by the car is 40\text{ km} for .

0.50\text{ hours}.

Concept:

The expression for the average can be written as:

S =\dfrac{{{\text{sum of distances }}}}{{{\text{sum of time}}}}    …… (1)

The distance travel by the car is 80\text{ km} for 1.00\text{ hours}, distance travel by the car is 50\text{ km} for 0.50\text{ hours} and distance travel by the car is 40\text{ km} for 0.50\text{ hours}.

The sum of the distance is:

\begin{aligned}D&=80{\text{ km}}+{\text{50 km}}+40{\text{ km}}\\&=170{\text{ km}}\end{aligned}

The sum of time taken to travel the distance is:

\begin{aligned}t&=1.00{\text{ h}} + 0.50{\text{ h}} + 0.50{\text{ h}}\\&=2.00{\text{ h}}\end{aligned}

Substitute 170\text{ km} for total distance and 2.00\text{ h} for total time in equation (1).

\begin{aligned}S&=\frac{{{\text{170 km}}}}{{2.00{\text{ h}}}}\\&=85{\text{ km/h}}\end{aligned}

Therefore, the average speed of the car for entire trip is \boxed{85\text{ km/h}}.

Learn more:

1. Find the net force. https://brainly.in/question/8668644

2. Find the velocity. https://brainly.in/question/4502003

3. Calculate average speed brainly.com/question/11597590

Answer Details:

Grade: Middle school

Subject: Physics

Chapter: Kinematics

Keywords:

Highway, car, driven, 80 km, 1.00 hour, 1.00 hr, 1.00 h, 50 km, 0.50 hour, 0.50 hr, 0.50 h, 50  km, average speed, entire, trip, 85 km/hr.

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Explanation:

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Time taken by phillippe \frac{20}{3.5}+\frac{20}{3.5-1.5}

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8 0
3 years ago
Read 2 more answers
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Answer:

What is the difference between the crust and lithosphere? The crust (whether continental or oceanic) is the thin layer of distinctive chemical composition overlying the ultramafic upper mantle. ... The lithosphere is the rigid outer layer of the Earth required by plate tectonic theory.

Explanation:

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4 0
2 years ago
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Six friends are at a pizzeria. They want to order enough pizza so that each person can eat at least 2/5 . ​ start fraction, 2, d
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Friend #1 gets at least 2/5 of a pizza.

Friend #2 gets at least 2/5 .

Friend #3 gets at least 2/5 .

Friend #4 gets at least 2/5 .

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Friend #6 gets at least 2/5 .

Sum . . . . . . . . . at least  12/5 of a pizza.

Simplify . . . . . . at least  2.4 pizzas.

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An elastic conducting material is stretched into a circular loop of 9.65 cm radius. It is placed with its plane perpendicular to
Nadya [2.5K]

Answer:

The induced emf in the coil is 0.522 volts.                        

Explanation:

Given that,

Radius of the circular loop, r = 9.65 cm

It is placed with its plane perpendicular to a uniform 1.14 T magnetic field.

The radius of the loop starts to shrink at an instantaneous rate of 75.6 cm/s , \dfrac{dr}{dt}=-0.756\ m/s

Due to the shrinking of radius of the loop, an emf induced in it. It is given by :

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(BA)}{dt}\\\\\epsilon=B\dfrac{-d(\pi r^2)}{dt}\\\\\epsilon=2\pi rB\dfrac{dr}{dt}\\\\\epsilon=2\pi \times 9.65\times 10^{-2}\times 1.14\times 0.756\\\\\epsilon=0.522\ V

So, the induced emf in the coil is 0.522 volts.                                

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