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olchik [2.2K]
3 years ago
13

Zero gauge wire has a diameter of 0.32in and can carry a sustained current of 150A safely. What is the magnetic field a distance

5cm from the center of a long straight segment of zero gauge wire carrying a current of 150A? This would be the field experienced by a bird sitting on the wire. Select One of the Following:
(a) 1.2 × 10−2T
(b) 1.9 × 10−3T
(c) 3.0 × 10−4T
(d) 6.0 × 10−4T
(e) 1.0 × 10−6T
Physics
1 answer:
DanielleElmas [232]3 years ago
5 0

Answer: d) 6*10^-4 T

Explanation: In order to explain this problem we have to use the Ampere law to calculate the magnetic field, which is given by:

∫B*dl=μo*I  then

B=μo*I/(2*π*r)  where r and I are the distance to the wire and the current in the wire. μo is equal 4*π*10^-7 Wb/A*m

Finally, we have:

B=4*π*10^-7*150/(2*π*0.05)=6*10^-4 T

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Equation of orbit under central force​
SOVA2 [1]

I found this on arxsiv.org: “The central force motion between two bodies about their center of mass can be reduced to an equivalent one body problem in terms of their reduced mass m and their relative radial distance r. ... The potential V (r) from which this force is derived is also a function of r alone, F = −VV, V ≡ V (r).”

Mark as BRAINLIEST?

8 0
3 years ago
A rubber balloon is filled with 1 L of air at 1 atm and 300 K and is then put into a cryogenic refrigerator at 100 K. The rubber
Kipish [7]

Answer:

The correct answers are

(a) It decreases to 1/3 L

(ii) is (c) It is constant

Explanation:

to solve this, we list out the number of knowns and unknowns so as to determine the correct equation to solve the problem

The given variables are as follows

Initial volume V1 = 1L

V2 = Unknown

Initial Temperature T1 = 300K

let us assume that the balloon is perfectly elastic

At 300K the balloon is filled and it stretches to maintain 1 atmosphere

at 100K the content of the balloon cools reducing the excitement of the gas content which also reduces the pressure, however, the balloon being perfectly elastic, contracts to maintain the 1 atmospheric pressure, hence the answer to (ii) is (c) It is constant,

For (i) since we know that the pressure of the balloon is constant

by Charles Law V1/T1 =V2/T2

or V2 = (V1/T1)×T2 =\frac{1L}{300K}× 100K= \frac{1}{3} × L = L/3 hence the correct answer to (i) is 1/3L

8 0
3 years ago
One of the harmonics of a string fixed at both ends has a frequency of 52.2 Hz and the next higher harmonic has a frequency of 6
Angelina_Jolie [31]

Solution :

Frequency may be defined as the number of observation or number of waves that is taken in per unit time. The unit of frequency is Hertz or Hz.

It is given that :

Successive harmonic frequencies, f = 52.2 Hz

and f' = 60.9 Hz

Therefore, fundamental frequency, F = f' - f

                                                           F = 60.9 - 52.2

                                                          F = 8.7 Hz

Therefore the string which is fixed at both the ends forms all the harmonics.

6 0
2 years ago
Can someone help me?
Setler [38]

Answer: (1, 30), (2,10), (3,40), (4,20)

Explanation:

4 0
3 years ago
Help me please this is for physics
Yuri [45]
<h2>Hello there! :)</h2>

It's a pleasure to be helping you today with your<u> physics question!</u>

Answer:

23.1m/s

Explanation:

We want to find the initial speed of the ball.

To do this, we have to apply the formula for the time of flight of a projectile:

T=\frac{2_{v0~sin 0} }{g}

where θ = angle of flight

g = acceleration due to gravity

v0 = initial speed

Therefore, substituting the given values into the formula, we have that:

\boxed{4.2=\frac{2~x~_{v0~sin63} }{9.8}}

⇒ 2 ×_{v0} ×0.8910= 9.8 × 4.2

⇒\boxed{{v0}=\frac{9.8~times~4.2}{2~times~0.8910}}

\boxed{{v0} =23.1m/s}

That is the initial speed of the ball.

<em />

<em>I hope this helps you!</em>

<em>Good Luck with your Assignment!</em>

3 0
2 years ago
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