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olchik [2.2K]
2 years ago
13

Zero gauge wire has a diameter of 0.32in and can carry a sustained current of 150A safely. What is the magnetic field a distance

5cm from the center of a long straight segment of zero gauge wire carrying a current of 150A? This would be the field experienced by a bird sitting on the wire. Select One of the Following:
(a) 1.2 × 10−2T
(b) 1.9 × 10−3T
(c) 3.0 × 10−4T
(d) 6.0 × 10−4T
(e) 1.0 × 10−6T
Physics
1 answer:
DanielleElmas [232]2 years ago
5 0

Answer: d) 6*10^-4 T

Explanation: In order to explain this problem we have to use the Ampere law to calculate the magnetic field, which is given by:

∫B*dl=μo*I  then

B=μo*I/(2*π*r)  where r and I are the distance to the wire and the current in the wire. μo is equal 4*π*10^-7 Wb/A*m

Finally, we have:

B=4*π*10^-7*150/(2*π*0.05)=6*10^-4 T

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LekaFEV [45]

The distance D where the object comes to rest is 1.08.m.

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(c) the distance D where the object comes to rest.

W_{total} =ΔKE ⇒ -0.25*1*9.8*D = 0-1/2*1*2.3^{2}

⇒D=\frac{0.5*2.3^{2} }{2.45}

⇒1.08.m

To learn more about distance, refer to:

brainly.com/question/4998732

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5 0
1 year ago
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blagie [28]

Answer:

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Explanation:

4 0
2 years ago
If it is brittle, dissolves easily in water, has a high melting point, and conducts electric current it is a(n) __________.
Julli [10]

Answer:

Ionic Compound

Explanation:

We know that an ionic compound dissolves easily in water. Its melting point is very high, and it is a conductor.

The equation for Ionic Compound (IC) versus Electricity (EC) is

IC=1/2 divided by EC

EC is the base for the mathematics, so EC is a base warmth at 360.

360 divided by 1/2 is 180

That is the speed in which the current has.

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A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110.m. Determine the acceleration
AlexFokin [52]
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6 0
3 years ago
A capacitor with air between its plates ischarged to 60 V and then disconnected fromthe battery. When a piece of glass is placed
-BARSIC- [3]

Answer:

       k = 1.30

Explanation:

For this exercise let's write the capacitance in air and with dielectric

air             C₀ = Q / DV

dielectric  C = k Q / DV

They tell us that the capacitor is charged and then the battery is disconnected, therefore the charge stored on the plate remains constant.

                         

therefore the capacitance a changes to the value

           C = k C₀

The voltage in the presence of dielectric must meet the relationship

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           k = ΔV₀ /ΔV

let's calculate

           k = 60/46

           k = 1.30

5 0
2 years ago
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