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Novay_Z [31]
3 years ago
12

Which kinds of objects emit visible light in the electromagnetic spectrum?

Physics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0

Answer: The correct answer is relatively hot objects.

Explanation:

Electromagnetic spectrum is a continuum of all the electromagnetic waves. They are arranged according to frequency and wavelength.

All objects emit wave according to their temperature.

The relatively hot objects emit the visible light or ultraviolet radiations having higher frequencies while the relatively cold objects emit wave of lower frequencies such as radio wave. The visible lights in the electromagnetic spectrum is seen by naked eyes.

The wavelengths of the visible light lies between 400 nm to 700 nm.

Therefore, the correct answer is relatively hot objects.

Triss [41]3 years ago
3 0

Answer : Relatively hot objects

Explanation : We know that, the temperature of the objects is inversely proportional to their wavelengths. The objects emitting radiation in the visible region have short wavelength and hence are relatively hotter.

We know the range of wavelength of the visible spectrum is from 400 nm to 780 nm.





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How large an expansion gap should be left between steel railroad rails if they may reach a maximum temperature 30.0°C greater th
irina [24]

Answer:

<em>1.2 cm</em>

Explanation:

<u>Thermal Expansion</u>

It's the tendency that materials have to change its size and/or shape under changes of temperature. It can be in one (linear), two (surface) or three (volume) dimensions.

The formula to compute the expansion of a material under a change of temperature from T_o to T_f is given by.

\Delta L=L_o.\alpha .(T_f-T_o)

Where Lo is the initial length and \alpha is the linear temperature expansion coefficient, which value is specific for each material. The data provided in the problem is as follows:

L_o=30\ m,\ T_f-T_o=30^oC,\ \alpha=13\times 10^{-6}\ ^oC^{-1}

Computing the expansion we have

\Delta L=30\times 13\times 10^{-6}(30)=0.0117=1.17\ cm

The expansion gap should be approximately 1.2 cm

6 0
3 years ago
5. Two charged spheres are separated by
soldier1979 [14.2K]

Answer:C

Explanation:

3 0
3 years ago
A surface completely surrounds a 3.3 × 10-6 C charge. Find the electric flux through this surface when the surface is (a) a sphe
KengaRu [80]

Answer:

Electric flux in a) , b) and c) is same which is   0.373 × 10 ⁶ N m²/C

Explanation:

given,

surface charge (q) = 3.3 × 10⁻⁶ C

to calculate electric flux = ?

a) radius = 0.76 m

area of sphere = 4 π r²

electric flux = \dfrac{q}{\varepsilon}

\varepsilon = 8.85 \times 10^{-12} C^2/Nm^2

electric flux =  \dfrac{3.3 \times 10^{-6}}{8.85 \times 10^{-12} }

flux = 0.373 × 10 ⁶ N m²/C

electric flux in the other two cases will also be same as electric flux is independent of area

so, Electric flux in a) , b) and c) is same which is   0.373 × 10 ⁶ N m²/C

5 0
4 years ago
An object is hung from a spring balance attached to the ceiling of an elevator cab. The balance reads 85 N when the elevator is
Ilia_Sergeevich [38]

Answer:

Explanation:

Balance force ( W ) = 85 N

a)  moving upward with constant velocity (V ) = 7.9 m/s.

The reading will not change since it is moving with constant velocity

  W = 85 N

b) Moving upward with V = 7.9 m/s and decelerating at the rate of (a ) = 1.1 m /s²

The net force ( F ) = W - ma

where m = W/g = 85/9.81 = 8.6646 kg

F = 85 - 8.6646 * 1.1 = 75.4689 N

4 0
3 years ago
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water vapor that has condensed and covers the ground in the morning

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