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Andrew [12]
3 years ago
14

Two or more velocities add by ____? Plz help

Physics
2 answers:
vichka [17]3 years ago
7 0

<u>Two or more velocities are added up by</u><u> vector addition method. </u>

Further Explanation:

The velocity is a vector quantity. A vector quantity is a unit that required the magnitude as well as the direction for its representation.

The velocity of a body is defined as the rate of change of displacement of the body in a particular direction. Since the velocity consists of the magnitude and the direction both, the simple method of addition cannot be applied for its addition.

The vector addition of the velocities comprise of the resultant magnitude of velocity as the angle made by the resultant.

The resultant magnitude of the velocity is given as:

\boxed{{v_r} = \sqrt {v_x^2 + v_y^2} }  

Here, {v_r} is the resultant magnitude and {v_x}\,\& \,{v_y} are the components of velocities in x and y directions.

The angle made by the resultant velocity is given by:

\boxed{\theta  = {{\tan }^{ - 1}}\dfrac{{{v_y}}}{{{v_x}}}}  

Thus, the addition of two or more velocities takes place by the vector addition method.

Learn More:

  1. Forces of attraction limit the motion of particles most in brainly.com/question/947434
  2. Three resistors ( r1 = 120 ohms, r2 = 330 ohms, and r3 = 240 ohms) and an ideal inductor (l = 1.6 mh) are connected to a battery brainly.com/question/1695461
  3. How is power defined brainly.com/question/911620

Answer Details:

Grade: High School

Chapter: Vectors and scalars

Subject: Physics

Keywords: Velocities, vectors. Scalar, vector addition, simple addition, magnitude and direction, components, x and y direction.  

VladimirAG [237]3 years ago
3 0
By vector addition.
In fact, velocity is a vector, with a magnitude intensity, a direction and a verse, so we can't simply do an algebraic sum of the two (or more velocities). 
First we need to decompose each velocity on both x- and y-axis (if we are on a 2D-plane), then we should do the algebraic sum of all the components on the x- axis and of all the components on the y-axis, to find the resultants on x- and y-axis. And finally, the magnitude of the resultant will be given by
R= \sqrt{(R_x)^2+(R_y)^2}
where Rx and Rx are the resultants on x- and y-axis. The direction of the resultant will be given by
\tan \alpha =  \frac{R_y}{R_x}
where \alpha is its direction with respect to the x-axis.
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4 years ago
A string along which waves can travel is 4.36 m long and has a mass of 222 g. The tension in the string is 60.0 N. What must be
lora16 [44]

Answer:

frequency is 195.467 Hz

Explanation:

given data

length L = 4.36 m

mass m = 222 g = 0.222 kg

tension T = 60 N

amplitude A = 6.43 mm = 6.43 × 10^{-3} m

power P = 54 W

to find out

frequency f

solution

first we find here density of string that is

density ( μ )= m/L ................1

μ = 0.222 / 4.36  

density μ is 0.050 kg/m

and speed of travelling wave

speed v = √(T/μ)       ...............2

speed v = √(60/0.050)

speed v = 34.64 m/s

and we find wavelength by power that is

power = μ×A²×ω²×v  /  2     ....................3

here ω is wavelength put value

54 = ( 0.050 ×(6.43 × 10^{-3})²×ω²× 34.64 )   /  2

0.050 ×(6.43 × 10^{-3})²×ω²× 34.64 = 108

ω² = 108 / 7.160  × 10^{-5}

ω = 1228.16 rad/s

so frequency will be

frequency = ω / 2π

frequency = 1228.16 / 2π

frequency is 195.467 Hz

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6 0
3 years ago
Agent Bond is standing on a bridge, 17 m above the road below, and his pursuers are getting too close for comfort. He spots a fl
faust18 [17]

Answer:

2 poles

Explanation:

We are told Agent Bond is standing on a bridge, 17 m above the road below.

Now, the bed of the truck is 1.5 m above the road.

It means the distance hewill need to fall = 17 - 1.5 = 15.5 m

acceleration due to gravity = 9.8 m/s²

Initial velocity = 0 m/s

Thus, to find the time, we will use the equation;

s = ut + ½at²

Plugging in the relevant values gives;

15.5 = 0 + ½9.8t²

Multiply through by 2 to give;

15.5 × 2 = 9.8t²

31 = 9.8t²

t² = 31/9.8

t = √(31/9.8)

t = 1.78 sec

We are told that he spots a flatbed truck approaching at 28 m/s and that the telephone poles are 22m apart.

Thus; The truck will pass the poles at a rate of; Velocity/distance between poles = 28/22 = 1.273 poles per second

Since, we got the time to be 1.78 seconds, then we can find the number of poles by multiplying it with the rate of poles per seconds.

Thus;

Number of poles = 1.78 second × 1.273 poles/ seconds = 2.27 poles

This is approximately 2 poles

6 0
3 years ago
A car accelerate uniformly from rest at 5m/s2 . Determine it's speed after 10s​
krek1111 [17]

Answer:

50m/s.

Explanation:

Let's take acceleration as A and speed as S:

A = 5m/s²

S = A × 10s = 5 × 10 = 50m/s

The answer is 50m/s.

6 0
4 years ago
Read 2 more answers
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