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2 years ago

Which of the following is an example of improving communication skills?

Physics

2 answers:

likoan [24]2 years ago

5 0

Answer:

Lena uses hand signals to tell Kim where to serve the volleyball against their opponents.

Explanation:

MissTica2 years ago

3 0

Answer:

You can improve those skills by practising new habits that make you a better communicator. That might include being more responsive to communications when they are sent, reminding yourself to make eye contact, practising giving positive feedback and asking questions in conversations.

Explanation:

I hope it's help u :)

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By what factor will the acceleration of an object change its mass stays constant but the force acting on it triples

Viktor [21]

Answer:

lacceleration is given by

a=F/m

With force acting on the object remained constant ,the acceleration is inversly proportional to mass of the object i.e with increase in mass =>acceleration decreases and with decrease in mass => acceleration increases.

acceleration decreases

acceleration increase

7 0

2 years ago

When is the pressure of the man on the ground more – lying position or standing position? Explain.

Dmitrij [34]

It is without a doubt in standing position!
“I will explain if u ask”
(Please mark brainlest if I helped u a bit)

3 0

2 years ago

The earth has a mass of 5.98 × 10^24 kg and the moon has a mass of 7.35 × 10^22 kg. The distance from the centre of the moon to

Leokris [45]

Answer:

F = 4.48N

Explanation:

In order to calculate the net gravitational force on the rocket, you take into account the formula for the gravitational force between two objects, which is given by:

$F=G\frac{m_1m_2}{r^2}$ (1)

G: Cavendish's constant = 6.674*10^-11 m^3kg^-1s^-2

r: distance between the objects

You have a rocket at the middle of the distance between Earth and Moon, then, you have opposite forces on the rocket.

If you assume the origin of a system of coordinates at the rocket position, with the Moon to the left and the Earth to the right, you have:

$F=G\frac{M_em}{r_1^2}-G\frac{M_mm}{r_2^2}$ (2)

Me: mass of the Earth = 5.98*10^24 kg

Mm: mass of the Moon = 7.35*10^22 kg

m: mass of the rocket = 1200kg

r1: distance from the rocket to the Earth = 3.0*10^8m

r: distance between rocket and Moon = 3.84*10^8m - 3.0*10^8m = 8.4*10^7m

You replace the values of the parameters in the equation (2):

$F=Gm[\frac{M_e}{r_1^2}-\frac{M_m}{r_2^2}]\\\\F=(6.674*10^{-11}m^3kg^{-1}s^{-2})(1200kg)[\frac{5.98*10^{24}kg}{(3.0*10^8m)^2}-\frac{7.35*10^{22}kg}{(8.4*10^7m)^2}]\\\\F=4.48N$

The net force exerted over the rocket is 4.48N

4 0

3 years ago

please help me and give an explanation

algol [13]

Answer:

write: I think that we can only see one side of the moon because the moon rotates and spins on its axis at the same rate that the Moon orbits the Earth.

hope this is wht ur looking for. :)

Explanation:

4 0

2 years ago

Would an oil ship moving at a speed of 10km/h have more or less momentum than a car moving at a speed of 100km/h? Explain your a

Rufina [12.5K]

Answer:

Multiply the mass times the speed for both, then compare.I would expect the mass of the oil ship to be more than 10 times the mass of the car, in which case its momentum would be greater.

PLZ MARK BRAINLIEST

7 0

2 years ago

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