Answer:
The scattering angle is 0.80
Explanation:
As we know
Wave length = h/mc (1-cos α) --1
W = mc^2
m = E/c^2
Substituting this in equation 1 we get
Wavelength = hc/E (1-cos α)
Substituting the given values, we get -
0.95*10^-9 = [(6.626 *10^-34 * 2.998 *10^8)/5.111*1000*1.6*10^-19} (1-cos α)
(1-cos α) = 1.14 *10^-10
cos α = 1- 1.14 *10^-10
α = 0.80
Answer:
We would have to locate the charge at the center of the triangle.
Explanation:
I tried my best to make geometric arguments, you can see the attached picture if it helps.
Let's say the triangle has three corners names 1, 2 and 3 as seen in the image. Let's determine the electric field at the center of the triangle. We can see that the x-component of electric field produced by the charge at 1 and the one produce by the charge at 2 will cancel each other out because they have the same but opposite values. The y components on the other hand are equal and are added. The magnitude of all three electric fields are the same (because each corner is at equal distance from the center and all three charges are equal, see the formula for the electric field: where is the distance between the point of observation and the charge). Thus lets call E the magnitude of the electric field produced by any of the charges.
We can clearly see that the y-component of the electric filed produced by 1 is , the same goes for the one produced by the charge at 2, knowing that , we have that the total field due to the charges at 1 and 2 are equal to E in the positive y-direction. The field produced by the third charge is clearly -E in the negative y-direction thus canceling the contribution from 1 and 2. The total electric field at the center of the triangle is zero, this also mean that any charge placed at that point will not feel any force.
Answer:
Explanation:
Parameters given;
Magnetic field intensity, B = 1.4 T
Speed of proton, v =
Mass of proton, m =
Charge of proton, q =
To find the acceleration of the proton, we first need to find the force exerted by the magnetic field on the proton:
F = q * v * B
F = * * 1.4
F =
This is the force exerted by the magnetic field on the proton. The force exerted by the proton has the same magnitude but an opposite direction as the force exerted by the magnetic field. Hence, = -
The force exerted by the proton is the product of its mass and acceleration. Hence, we can find its acceleration:
= ma
a = F/m
The magnitude, |a|, will be:
|a| =| |
|a| =
The magnitude of the acceleration of the proton is |a|
Answer:
Part a)
Part b)
Explanation:
Magnetic field due to outer solenoid inside it is given as
Now similarly we have
magnetic field due to inner solenoid on it axis is given as
Part a)
Now if a proton is revolving around the common axis of two solenoids
then we will have
Part b)
Now proton is revolving in the field of outer cylinder only
so again we have
Metals can form a sea of elections which causes them to be good conductors of energy