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just olya [345]
3 years ago
10

Which of the following is an example of improving communication skills?

Physics
2 answers:
likoan [24]3 years ago
5 0

Answer:

Lena uses hand signals to tell Kim where to serve the volleyball against their opponents.

Explanation:

MissTica3 years ago
3 0

Answer:

You can improve those skills by practising new habits that make you a better communicator. That might include being more responsive to communications when they are sent, reminding yourself to make eye contact, practising giving positive feedback and asking questions in conversations.

Explanation:

I hope it's help u :)

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10. Which of the following is an acceleration?<br> a. 12 m/s2 down<br> b. 5 m/s up<br> c. 8N West
nadya68 [22]

Answer:

a. 12 m/s² down

Explanation:

Acceleration has units of length per time squared.  Acceleration is a vector, so it also has a direction.

3 0
3 years ago
What type of stars will potentially one day
xz_007 [3.2K]

Answer:

2, High mass stars.

Add-on:

i hope this helped at all. im sorry if its incorrect.

4 0
2 years ago
Please help me answer the following question!
Troyanec [42]

Answer:

P = 0

Explanation:

Momentum is defined as the quentity of motion contained in a body. Mathematically, it can be defined as the product of mass and velocity. So, in order to determine the Volkswagen Beetle, at rest, we can use the simple formula, as follows:

where,

P = Momentum of Volkswagen Beetle = ?

m = Mass of Volkswagen Beetle = 750 kg

v = Velocity of Volkswagen Beetle = 0 m/s (since, it is at rest)

Therefore,

P =

3 0
2 years ago
How much force would be needed to cause a 4.6kg object to accelerate at 9.2m/s/s? *
poizon [28]

Answer:

<h2>42.32 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 4.6 × 9.2

We have the final answer as

<h3>42.32 N</h3>

Hope this helps you

5 0
3 years ago
An electron in the n = 7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 397 nm. what is the value
Dimas [21]

Answer:

n_f=2

Explanation:

It is given that,

Initially, the electron is in n = 7 energy level. When it relaxes to a lower energy level, emitting light of 397 nm. We need to find the value of n for the level to which the electron relaxed. It can be calculate using the formula as :

\dfrac{1}{\lambda}=R(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})

\dfrac{1}{397\times 10^{-9}\ m}=R(\dfrac{1}{n_f^2}-\dfrac{1}{(7)^2})

R = Rydberg constant, R=1.097\times 10^7\ m^{-1}

\dfrac{1}{397\times 10^{-9}\ m}=1.097\times 10^7\ m^{-1}\times (\dfrac{1}{n_f^2}-\dfrac{1}{(7)^2})

Solving above equation we get the value of final n is,

n_f=2.04

or

n_f=2

So, it will relax in the n = 2. Hence, this is the required solution.        

6 0
3 years ago
Read 2 more answers
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