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Vika [28.1K]
3 years ago
14

The acceleration of an object is constant when its velocity is :

Physics
2 answers:
bixtya [17]3 years ago
6 0
A) Constant.
That’s my answer!
emmasim [6.3K]3 years ago
5 0

Answer:

B. changing by a constant amount each second

Explanation:

thats my answer

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What are organelles?<br>Which part of a cell holds organelles?​
DanielleElmas [232]

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An organelle is a structure in a cell that has specific jobs to do. Organelles are held in the cytoplasm

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3 years ago
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What two quantities must stay the same in order for an object to have a constant velocity? A) The speed and kinetic energy must
GarryVolchara [31]

the answer is c) the speed and direction of travel must be constant


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3 years ago
Two forces (4N and 3N) pull your the left, while a 12N force pulls to the right. What is the net force
Lapatulllka [165]

Answer:

The answer is 11N to the right

Explanation:

Because 4N-3N= 1N

Therefore, 12N-1N=11N

The netforce is 11N to the right, because the greatest force is 12N to the right so it is more likely that the object is being pulled to the right.

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2 years ago
How to find the sum of a convergent series
Harlamova29_29 [7]

The formula that can be used to obtain a convergent series is given by;

a/1 – r.

<h3>What is a series?</h3>

In mathematics, we define a series as sum of numbers which could be convergent or divergent. In a convergent series, the summation of the numbers approaches a given value.

The formula that can be used to obtain a convergent series is given by;

a/1 – r.

Learn more about a convergent series:brainly.com/question/15415793?

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8 0
1 year ago
A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800
Arada [10]

Explanation:

The given data is as follows.

            m = 5000 kg,            h = 800 km = 0.8 \times 10^{6} m

    R_{e} = 6.37 \times 10^{6} m,    r = R + h = 7.17 \times 10^{6} m

   M_{e} = 5.98 \times 10^{24} kg,   G = 6.67 \times 10^{-11} Nm^{2}/kg^{2}

As we know that,

              \frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}

                      v = \sqrt{\frac{GM_{e}}{r^{2}}}

And, it is known that formula to calculate angular velocity is as follows.

               \omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}

                            v = \sqrt{\frac{GM_{e}}{r^{3}}}

                               = \sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}

                                = 1.0402 \times 10^{-3} rad/s

Thus, we can conclude that speed of the satellite is 1.0402 \times 10^{-3} rad/s.

6 0
2 years ago
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