1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gennadij [26K]
3 years ago
5

Determine which of the following moving objects obey the equations of projectile motion developed in this topic. A ball is throw

n in an arbitrary direction. A jet airplane crosses the sky with its engines thrusting the plane forward. A rocket leaves the launch pad. A rocket moves through the sky after its engines have failed. A stone is thrown under water.
Physics
1 answer:
Morgarella [4.7K]3 years ago
5 0

Answer:

A ball is thrown in an arbitrary direction and a rocket moves through the sky after its engines have failed.

Explanation:

The concept applied is that of projectile motion which is the free fall for both then horizontal and vertical component of a constant velocity. it is also the motion of an object thrown under the influence of acceleration due to gravity.

The correct option are as follows ; A ball is thrown in an arbitrary direction and a rocket moves through the sky after its engines have failed.

For the first case ; A ball is thrown in an arbitrary direction ; after the ball must have been thrown, the projectile further moves in a curved path.

for the second case ; A rocket moves through the sky after its engines have failed ; the rocket also moves in a curved path under the influence of the acceleration due to gravity.

You might be interested in
A push of magnitude P acts on a box of weight W as shown in the figure. The push is directed at an angle θ below the horizontal,
Kipish [7]

Answer:

its on wheels and they are supposed to make it eas

Explanation:

3 0
3 years ago
Ballistic data obtained on a firing range show that aerodynamic drag reduces the speed of a .44 magnum revolver bullet from 250
m_a_m_a [10]

Answer:

0.363999909622

Explanation:

F = Force

m = Mass = 15.6 g

C = Drag coefficient

ρ = Density of air = 1.21 kg/m³

A = Surface area = \dfrac{\pi}{4}d^2

v = Terminal velocity = v=210\ m/s

s = Displacement = 150 m

a=\dfrac{v^2-u^2}{2s}

Force is given by

F = ma

F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622

The drag coefficient is 0.363999909622 (ignoring negative sign)

4 0
3 years ago
Two hikers are 15 miles apart and walking toward each other. They meet in 2 hours. Find the rate of each hiker if one hiker walk
Marat540 [252]

Answer:

1- 2.6 mph

2- 4.9 mph

Explanation:

See attachment

4 0
4 years ago
The uniform 100-kg I-beam is supported initially by its end rollers on the horizontal surface at A and B. by means of the cable
Ann [662]

I attached a free body diagram for a better understanding of this problem.

We start making summation of Moments in A,

\sum M_A = 0

P(6cos\theta)-981(4cos\theta)=0

P=654N

Then we make a summation of Forces in Y,

\sum F_y = 0

654+R-981 = 0

R=327N

At the end we calculate the angle with the sin.

sin\theta = \frac{3m}{4m+2m+2m} = \frac{3m}{8m}

\theta = 22.02\°

8 0
3 years ago
A roller coaster has a vertical loop with radius 25.7 m. With what minimum speed should the roller-coaster car be moving at the
gogolik [260]

Answer:

15.88m/s

Explanation:

At the top of the roller coaster you will have three forces acting on the roller-coaster. See the image below. Fc is the centripetal force (for an object in circular motion), Fg is the gravitational force, and Fn is the normal force. To achieve the minimum speed we assume the roller-coaster is barely touching the vertical loop and so the normal force is zero. This leaves two acting forces.

F_g = F_c\\mg = \frac{m\times v^2}{r}\\v = \sqrt{gr} = \sqrt{9.81 \times 25.7}  = 15.88 m/s

7 0
3 years ago
Other questions:
  • A gas is placed in a storage tank at a pressure of 49.2 atm at 39.0C . As a safety device, a small metal plug in the tank is mad
    8·1 answer
  • What percentage of water vapor is found in the air
    10·2 answers
  • 1
    7·1 answer
  • PLSEAE HELP ME I WILL GIVE BRIANLYEST!!!!
    5·1 answer
  • How can I rewrite the equation a - b = d using addition?
    8·1 answer
  • Click the links to open the resources below. These resources will help you complete the assignment. Once you have created your f
    9·1 answer
  • Use correct alternative to complete the indirect speech sentence​
    6·1 answer
  • If you are sitting in a bus that is traveling along a straight, level road at 100 km/hr., you are traveling at 100 km/hr too. (a
    14·1 answer
  • 2 spheres are made from the same material. One is smaller and one is larger. Is the smaller sphere made up of smaller atoms than
    10·2 answers
  • 3. What is the density of a substance that weighs 39.1 g and is 56.0 mL?<br> (Density = g/mL)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!