Answer:
(1) 10^−2 m
Explanation:
The diameter of the tire of an automobile is generally expressed in centimetres; we can say that the diameter of a tire is generally about
d = 20 cm (20 centimetres)
Now we have to verify which option is closest to this value. To do that, we have to keep in mind the equivalence between metres and centimetres; in fact, we have:
This means that we can rewrite the diameter of the tire of a car as
By comparing it with the given options, we see that the closest option is
(1) 10^−2 m
which is therefore the correct answer.
Answer:
105.1N
Explanation:
According to the newton second law
Since the acceleration is zero, then;
Since;
Given the following
mass of ladder m = 14kg
acceleration due to gravity g = 9.8m/s²
θ = 50°
Substitute
Hence the magnitude of the friction force (in N) exerted on the ladder in the point of contact with the horizontal surface is 105.1N
A) 2250 meters from starting pont
b) 90 degrees to the right
Terminal velocity is the maximum velocity attainable by an object as it falls through a fluid and is given by,
Where,
m = mass of the falling object.
g = the acceleration due to gravity.
\rho = the density of the fluid the object is falling through.
A = the projected area of the object.
C = the drag coefficient.
A) Because a drop is difficult to approximate to a certain form, it usually tends to be considered a spectrum, the terminal velocity for a sphere is given by
Whatever our appreciations, all the variables are constant, except for the Diameter, we can realize that the terminal velocity is proportional to the radius of the object, the greater the radius - the larger the drop - the greater the terminal velocity.
B) Since there is a "constant" terminal velocity at the end of the path, at which point the forces are balanced, the acceleration will be 0. For both objects.
