Let g(x) = 5x -2 and h(x)= x^2-16

1 answer:

3 0

$\bf \begin{cases}
g(x)=5x-2\\
h(x)=x^2-16
\end{cases}\qquad (h\circ g)(x)\implies h(~g(x)~)
\\\\\\
g(\stackrel{\downarrow }{-1})=5(\stackrel{\downarrow }{-1})-2\implies g(-1)=-5-2\implies \boxed{g(-1)=-7}\\\\
-------------------------------\\\\
(h\circ g)(-1)\implies h(~g(-1)~)\implies h\left( \boxed{-7} \right)
\\\\\\
h(\stackrel{\downarrow }{-7})=(\stackrel{\downarrow }{-7})^2-16\implies h(-7)=49-16\implies \stackrel{(h\circ g)(-1)}{h(-7)=33}$

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You are getting a line-up ready for a school kickball game. You have 7 girls and 7 boys. The rules state each child must kick th

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Answer:

50,803,200 ways

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