The displacement volume in liters is 2.74 liters.
<h3>What is displacement volume?</h3>
Displacement volume is the quantity of solvent that will be displaced by a specified quantity of a solid during dissolution.
It can also be defined as the volume displaced by the piston as it moves between top dead center and bottom dead center in a car engine.
<h3>Displacement volume in liters</h3>
1 liter = 61.02 in³
? = 167 in³
= 167/61.02
= 2.74 liters
Thus, the displacement volume in liters is 2.74 liters.
Learn more about displacement volume here: brainly.com/question/1945909
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B and c
because they aren't moving,
so when and if they do move
they will gain kinetic energy,
but for now they have potential
energy. hope I could help :))
To find the tangent plane to the surface f(x,y,z)=0 at a point (X,Y,Z) we use the following method:
<span>Calculate grad f = (f_x, f_y, f_z). The normal vector to the surface at the point (X,Y,Z) is grad f(X,Y,Z). The equation of a plane with normal vector n which passes through the point p is (r-p).n=0, where r=(x,y,z) is the position vector. So the equation of the tangent plane to the surface through the point (X,Y,Z) is ((x,y,z)-(X,Y,Z)).grad f(X,Y,Z)=0. </span>
<span>Now in your case we have f(x,y,z)=y-x^2-z^2, so grad f=(-2x,1,-2z), and the equation of the tangent plane at the point (X,Y,Z) is </span>
<span>((x,y,z)-(X,Y,Z)).(-2X,1,-2Z)=0, </span>
<span>that is </span>
<span>-2X(x-X)+1(y-Y)-2Z(z-Z)=0, </span>
<span>i.e. </span>
<span>-2Xx+y-2Zz = -2X^2+Y-2Z^2. (1) </span>
<span>Now compare this equation with the plane </span>
<span>x + 2y + 3z = 1. (2) </span>
<span>The two planes a_1x+b_1y+c_1z=d_1, a_2x+b_2y+c_2z=d_2 are parallel when (a_1,b_1,c_1) is a multiple of (a_2,b_2,c_2). So the two planes (1),(2) are parallel when (-2X,1,-2Z) is a multiple of (1,2,3), and we have </span>
<span>(-2X,1,-2Z)=1/2(1,2,3) </span>
<span>for X=-1/4 and Z=-3/4. On the paraboloid the corresponding y coordinate is Y=X^2+Z^2=1^4+9^4=5/2. </span>
<span>So the tangent plane to the given paraboloid at the point (-1/4,5/2,-3/4) is parallel to the given plane.</span>
Answer:
Spacecraft's speed relative to Earth is 0.14c .
Explanation:
Let v be the speed of the spacecraft with respect to Earth's frame. According to special theory of relativity, there is time dilation i.e. given by the relation :
t = t₀γ
Here t is time measured in moving frame, t₀ is time measured in rest frame and γ is constant.
We know that γ =
Here c is the speed of light.
So, t = .......(1)
According to the problem, the time measure in Earth's frame is :
t₀ = 1 hr = 60 min =60 x 60 s = 3600 s
The time measured in the space craft frame is :
t = 3601 s
Substitute t and t₀ in equation (1) :
3601 =
v = 0.14 c