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Tom [10]
3 years ago
5

How did kepler descrube the planets orbits​

Physics
1 answer:
Natalka [10]3 years ago
4 0

Answer:

The planet follows the ellipse in its orbit, meaning that the planet to Sun distance is constantly changing as the planet goes around its orbit. Kepler's Second Law: the imaginary line joining a planet and the sons sweeps equal areas of space during equal time intervals as the planet orbits.

(Brainliest, please?)

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Reflecting telescopes are popular because they're
musickatia [10]
<span>The answer is letter C.

Reflecting telescopes are more powerful than refracting telescopes. These are also called as reflectors which serves an optical telescope that uses a single or combination of curved mirrors. These mirrors then reflect light and form an image. It is designed for very large diameter objects and are mostly considered as major telescopes in the field of astronomy. They were used as an alternative for refracting telescopes during the 17th century because they suffer less chromatic aberrations than a refracting telescope does. <span>
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7 0
3 years ago
Using complete sentences and your own words describe some of the ways humans use water.
Lera25 [3.4K]

Answer:

Humans use water for many different things. We use water to stay hydrated. Our bodies need water to live. Back in the day people used water for transportation and trading. This was a way to become wealthy and exchange goods and ideas from one place to another. We also use water to clean ourselves off. If we don't we can become sick with illnesses that can harm our bodies.

Explanation:

6 0
3 years ago
The FM radio band in most places goes from frequencies of about 89 MHz to 106 MHz. How long is the wavelength of the radiation a
ohaa [14]

Answer:

2.83 m

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is given by

\lambda=\frac{c}{f}

where

\lambda is the wavelength

c=3.0\cdot 10^8 m/s is the speed of light

f is the frequency

For the FM radio waves in this problem, we have:

f_1=89 MHz=89\cdot 10^6 Hz is the minimum frequency, so the maximum wavelength is

\lambda_2=\frac{c}{f_1}=\frac{3\cdot 10^8}{89\cdot 10^6}=3.37 m

The maximum frequency is instead

f_2=106 MHz=106\cdot 10^6 Hz

Therefore, the minimum wavelength is

\lambda_1=\frac{c}{f_2}=\frac{3\cdot 10^8}{106\cdot 10^6}=2.83 m

So, the wavelength at the beginning of the range is 2.83 m.

8 0
3 years ago
When a 0.350-kg package is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The package is now di
AleksandrR [38]

To solve the problem it is necessary to use the concepts related to the calculation of periods by means of a spring constant.

We know that by Hooke's law

F=kx

Where,

k = Spring constant

x = Displacement

Re-arrange to find k,

k= \frac{F}{x}

k= \frac{mg}{x}

k= \frac{(0.35)(9.8)}{12*10^{-2}}

k = 28.58N/m

Perioricity in an elastic body is defined by

T = 2\pi \sqrt{\frac{m}{k}}

Where,

m = Mass

k = Spring constant

T = 2\pi \sqrt{\frac{0.35}{28.58}}

T = 0.685s

Therefore the period of the oscillations is 0.685s

4 0
3 years ago
The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is_____
Bond [772]
When you are talking about calculating the kinetic energy of an object, the formula is as stated:

Ek =1/2mv²

Where m is mass and v is velocity. Sub all those numbers in and you'll get 25J of kinetic energy.
3 0
3 years ago
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