Answer:
121.78 g
Explanation:
You multiply the mols by the grams in one mol.
A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.
<h3>What is Stoichiometry ?</h3>
Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
According to Stoichiometry
![7\ \text{mol C} \times \frac{1\ \text{mol O}}{1\ \text{mol C}}](https://tex.z-dn.net/?f=7%5C%20%5Ctext%7Bmol%20C%7D%20%5Ctimes%20%5Cfrac%7B1%5C%20%5Ctext%7Bmol%20O%7D%7D%7B1%5C%20%5Ctext%7Bmol%20C%7D%7D)
= 7 mol O
Thus from the above conclusion we can say that A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.
Learn more about the Stoichiometry here: brainly.com/question/16060223
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: This is the chemical formula for Nickel Tetracarbonyl (a powerfully poisonous liquid used in Nickel Refining).
Ni(CO)₄
A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. How many moles of oxygen are in the sample ?
Answer:
49.2°C is the temperature
Explanation:
Based on Charles's law, the absolute temperature of a gas is directly proportional to the volume under constant pressure. The equation is:
V1 / T1 = V2 / T2
<em>Where V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.</em>
<em />
Computing the values of the problem:
V1 = 0.432L
T1 = -20.0°C + 273.15K = 253.15K
V2 = 0.550L
T2 = ?
0.432L / 253.15K = 0.550L / T2
322.3K = T2
322.3K - 273.15 =
<h3>49.2°C is the temperature</h3>
Answer:
B
Explanation:
From charles' law,
![v \alpha t](https://tex.z-dn.net/?f=v%20%5Calpha%20t)
where v is volume and t is absolute temperature
![\frac{v1}{t1} = \frac{v2}{t2}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bv1%7D%7Bt1%7D%20%20%3D%20%20%5Cfrac%7Bv2%7D%7Bt2%7D%20)
![v1 = 0.5l \\ t1 = (22 + 273 )k\\ t2 = (4 + 273)k \\ t1 = 295k \\ t2 = 277k \\ \frac{0.5}{295} = \frac{v2}{277} \\ v2 = 277 \times \frac{0.5}{295} = 0.47l](https://tex.z-dn.net/?f=v1%20%3D%200.5l%20%5C%5C%20t1%20%3D%20%2822%20%2B%20273%20%29k%5C%5C%20t2%20%3D%20%284%20%2B%20273%29k%20%5C%5C%20t1%20%3D%20295k%20%5C%5C%20t2%20%3D%20277k%20%5C%5C%20%20%5Cfrac%7B0.5%7D%7B295%7D%20%20%3D%20%20%5Cfrac%7Bv2%7D%7B277%7D%20%20%5C%5C%20v2%20%3D%20277%20%5Ctimes%20%5Cfrac%7B0.5%7D%7B295%7D%20%20%3D%200.47l)
- Hence that's it
Answer:
Empirical CHO
molecular C4H4O4
Explanation:
From the question, we know that it contains 41.39% C , 3.47% H and the rest oxygen. To get the % composition of the oxygen, we simply add the carbon and hydrogen together and subtract from 100%.
This means : O = 100 - 41.39 - 3.47 = 55.14%
Next is to divide the percentage compositions by their atomic masses.
C = 41.39/12 = 3.45
O = 55.14/16 = 3.45
H = 3.47/1 = 3.47
Now we divide by the smallest value which is 3.45. We can deduce that this will definitely give us an answer of 1 all through as the values are very similar.
Hence the empirical formula of Maleic acid is CHO
Now we go on to deduce the molecular formula.
To do this we need the molar mass. I.e the amount in grammes per one mole of the compound.
Now we can see that 0.378mole = 43.8g
Then 1 mole = xg
x = (43.8*1)/0.378 = 115.87 = apprx 116
[CHO]n = 116
(12 + 1 + 16]n = 116
29n = 116
n = 116/29 = 4
The molecular formula is thus C4H4O4