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3 years ago

6

A weighted coin that comes up heads with probability 0.6 is flipped n times. find the probability that the total number of heads

in these flipds exceeds

1 answer:

malfutka [58]3 years ago

5 0

Im pretty sure you don't need help with this.this is from a week ago

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What is the answer for x?

Crank

Step-by-step explanation:

$180 = 70 + 90 + y \\ y = 20 \\ (x + y + 18) + 44 + 90 = 180 \\ y = 8$

8 0

2 years ago

Please help on this question?

svlad2 [7]

Well we know these two angles are congruent, so we set their angles equal to each other.
5w - 69 = w + 3
4w = 72
w = 18
Now we plug w back into one of the equations, and then multiply whatever number we get by 2.
18 + 3 = 21
21 x 2 = 42
The measure of STU is 42°

4 0

3 years ago

What would be the first step to solve for n in the equation 3n-7=30?

taurus [48]

The first step would be to add 7 to both sides.
3n-7=30
add 7
3n=37
divide by 3
n=12.33

4 0

2 years ago

Read 2 more answers

Evaluate the expression for x=5, y=3,and z=1/4. <br> 5x−6y+20z/4yz

Anna11 [10]

Just substitute each number into the expression:
5(5) - 6(3) + 20(1/4)/4(3)(1/4) = 25 - 18 + 5/3 = 7 + 5/3 = 26/3 or 8 and 2/3.

4 0

3 years ago

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Verify that the given point is on the curve and find the lines that are (a) tangent and (b) normal to the curve at the given poi

lara [203]

For each curve, plug in the given point $(x,y)$ and check if the equality holds. For example:

(I) (2, 3) does lie on $x^2+xy-y^2=1$ since 2^2 + 2*3 - 3^2 = 4 + 6 - 9 = 1.

For part (a), compute the derivative $\frac{\mathrm dy}{\mathrm dx}$ , and evaluate it for the given point $(x,y)$ . This is the slope of the tangent line at the point. For example:

(I) The derivative is

$x^2+xy-y^2=1\overset{\frac{\mathrm d}{\mathrm dx}}{\implies}2x+x\dfrac{\mathrm dy}{\mathrm dx}+y-2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x+y}{2y-x}$

so the slope of the tangent at (2, 3) is

$\dfrac{\mathrm dy}{\mathrm dx}(2,3)=\dfrac74$

and its equation is then

$y-3=\dfrac74(x-2)\implies y=\dfrac74x-\dfrac12$

For part (b), recall that normal lines are perpendicular to tangent lines, so their slopes are negative reciprocals of the slopes of the tangents, $-\frac1{\frac{\mathrm dy}{\mathrm dx}}$ . For example:

(I) The tangent has slope 7/4, so the normal has slope -4/7. Then the normal line has equation

$y-3=-\dfrac47(x-2)\implies y=-\dfrac47x+\dfrac{29}7$

3 0

3 years ago