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Contact [7]
3 years ago
13

Mandy is skating at 5 miles per hour . Nikki is skating at 6 miles per hour and started 1 mile behind Mandy. If their rates stay

the same will Mandy catch up with Nikki? Explain.
Mathematics
1 answer:
Anna11 [10]3 years ago
6 0

Answer,

YES, if their rates stay the same, Nikki will catch up with Mandy in 1 hour

 

EXPLANATION

Mandy’s speed is 5 miles per hour

Distance covered = Speed * time

Mandy’s distance covered at time, t = 5t

Therefore, her position at time t = 5t

 

Nikki’s speed is 6 miles per hour

Distance covered = Speed * time

Nikki’s distance covered at time, t = 6t

Since Nikki started 1 mile behind Mandy, her position at time t = 6t - 1

 

If Nikki will catch up with Mandy, then there must be a real value for t, t which both Nikki and Mandy are at the same position

 

Testing if there is a real value for t where, 5t = 6t – 1

5t = 6t – 1

6t – 1 = 5t

 

Add 1 to both sides of the equation

6t – 1+ 1 = 5t + 1

6t = 5t + 1

 

Subtract 5t from both sides of the equation

6t – 5t = 5t – 5t + 1

t = 1

 

1 is a real value; this means after they have both skated for 1 hour Nikki will catch up with Mandy.

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Jason has 10 dimes and 2 nickels

because each dime equals 10 cent

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2 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
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A) 0.9803; 0.4803
B) 32

We calculate the z-score for this problem by using the formula:

z=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}

Using our formula, we have:

z=\frac{3.00-2.65}{\frac{0.85}{\sqrt{25}}}=2.06

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.9803.

To find the probability it is between the mean and this, we subtract the probability associated with the mean (0.5) from this:
0.9803 - 0.5 = 0.4803.

To find B, we first find the z-score for this.  Using a z-table (http://www.z-table.com) we see that the closest z-score would be 2.33.  We then set up our equation as

2.33=\frac{3.00-2.65}{\frac{0.85}{\sqrt{n}}}=\frac{0.35}{\frac{0.85}{\sqrt{n}}}&#10;\\&#10;\\2.33=0.35\div \frac{0.85}{\sqrt{n}}=0.35\times \frac{\sqrt{n}}{0.85}

Multiplying both sides by 0.85 we have
2.33(0.85) = 0.35√n
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Divide both sides by 0.35:
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Square both sides:
(1.9805/0.35)² = n
32 ≈ n
8 0
3 years ago
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