Answer:
The concentration resulting solution = 0.350 M
Explanation:
In case of dilution , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = initial concentration ,
V₁ = initial volume ,
M₂ = final concentration , i.e. , concentration after dilution ,
V₂ = final volume .
from , the question ,
M₁ = 0.85 M
V₁ = 4.12 L
M₂ = ?
V₂ = 10.0 L
Using the above formula , the molarity of the final solution after dilution , can be calculated as ,
M₁V₁ = M₂V₂
0.85 M * 4.12 L = M₂ * 10.0 L
M₂ = 0.85 M * 4.12 L / 10.0 L
M₂ = 0.350 M
the mass of substance c is twice of substance b. we know this through the law of conservation, so 12 > 4 + _, so substance C is 8, which is twice B
