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Cerrena [4.2K]
3 years ago
12

Salts usually have a low melting point

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
8 0
Yes they do if that was your question
Afina-wow [57]3 years ago
6 0
Yes in fact it does!
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13.50 grams of Pb(NO3)4 are dissolved in enough water to make 250 mL of solution. What is the molar its of the resulting solutio
likoan [24]
Data:
M (molarity) = ? (M or Mol/L)
m (mass) = 13.50 g
V (volume) = 250 mL → 0.25 L
MM (Molar Mass) of Lead(IV) Nitrate Pb(NO_3)_4
Pb = 1*207 = 207 amu
N = (1*14)*4 = 14*4 = 56 amu
O = (3*16)*4 = 48*4 = 192 amu
------------------------------------
MM of Pb(NO_3)_4 = 207+56+192 = 455 g/mol

Formula:
M =  \frac{m}{MM*V}

Solving:
M = \frac{m}{MM*V}
M =  \frac{13.50}{455*0.25}
M =  \frac{13.50}{113.75}
M = 0.118681318...\:\:\to\:\:\boxed{\boxed{M \approx 0.119\:Mol/L}}\end{array}}\qquad\quad\checkmark

Answer:
<span>B. 0.119 M</span>
5 0
3 years ago
Can somebody help me please? it’s urgent
Anettt [7]

Answers:

See attached table

Explanation:

The isotope symbol will have the mass number and chemical symbol.  The atomic number will be equal to the number of protons because the atomic number is the number of protons in an atom.  The electrons will be equal to the protons because the atom is neutral.  The neutrons can be found by subtracting the number of protons from the mass number.  The mass number can be found by adding the protons and neutrons.  It is also in the name of the isotope.

4 0
2 years ago
The orbit of a planet is an ellipse with the sunat one of the foci.. This is Kepler's........ second law third law first law​
Svetradugi [14.3K]

Answer:

its keplers first law

Explanation:

answer from gauth math

6 0
2 years ago
What is the empirical formula of a compound with a % composition of 40.1% sulfur and 59.9% oxygen?
olga_2 [115]

Answer:

The empirical formula is SO

Explanation:

The empirical formula of a chemical compound is the simplest positive integer ratio of atoms present in a compound.

Given 40.1% Sulphur and 59.9% oxygen.

We have to assume the mass of the compound to make our calculations easy.

Let's assume that the mass of the compound is 100g, that the mass of sulphur will be 40.1g and the mass of oxygen will then be 59.9g.

Number of moles= reacting mass/ molar mass

Molar mass of Sulphur = 32g/mol

Molar mass of Oxygen = 16g/mol

No of moles of S= 40.1g/100g

=0.401 moles of S

No of moles of O = 59.9g/100g

=0.599 moles of O

•These are the relative mole ratios for the compound,

•They need to be converted from decimals into whole numbers

•Turn mole ratio into whole number ratio by dividing by all the elements by the least/smallest number of moles calculated.

Number of moles of S = 0.401moles/0.401 = 1 mol S

Number of moles of O = 0.599moles/0.401 = 1.49 mol O which is approximately 1 (to the nearest whole number, considering it tenths' value which is 4 and less than 5)

The empirical formula is therefore SO.

4 0
3 years ago
State Henry's law. Give an example of Henry's law.
ruslelena [56]

Answer:

Found this off of google, "Henry's law comes into play every time a bottle of Pepsi (or any other carbonated drink) is opened. The gas above the unopened carbonated drink is usually pure carbon dioxide, kept at a pressure which is slightly above the standard atmospheric pressure."

4 0
2 years ago
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