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Lina20 [59]
3 years ago
13

How can a driver steer a car traveling at constant speed so that the magnitude of the acceleration remains constant. (Assume tha

t the road is level. Select all that apply.)
1. on a circular path
2. on a straight line
3. on a parabolic path
4. on an elliptical path
Physics
1 answer:
ratelena [41]3 years ago
3 0

<h2>Circular path i.e 1</h2>

Explanation:

If the driver steer into circular path , the acceleration of car will be

acceleration = velocity²/radius  of circle

Because the velocity and radius of circle are both constant at all points . Thus the acceleration will also remain constant .

In case 3 and 4 , the radius of path changes . Because velocity is constant . Therefore the acceleration will not remain constant

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Determine the vector perpendicular to the plane of A= 31+ 6j - 2k and B=4i-j +3k
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The vector perpendicular to the plane of A = 3i+ 6j - 2k and B = 4i-j +3k is 16 i - 17 j - 27 k

Let r be the vector perpendicular to A and B,

r = A * B

A = 3i + 6j - 2k

B = 4i - j + 3k

a1 = 3

a2 = 6

a3 = - 2

b1 = 4

b2 = - 1

b3 = 3

a * b = ( a2 b3 - b2 a3 ) i + ( a3 b1 - b3 a1 ) j + ( a1 b2 - b1 a2 ) k

a * b = [ ( 6 * 3 ) - ( - 1 * - 2 ) ] i + [ ( - 2 * 4 ) - ( 3 * 3 ) ] j + [ ( 3 * - 1 ) - ( 4 * 6 ) ] k

a * b = 16 i - 17 j - 27 k

The perpendicular vector, r = 16 i - 17 j - 27 k

Therefore, the vector perpendicular to the plane of A = 3i + 6j - 2k and B = 4i - j + 3k is 16 i - 17 j - 27 k

To know more about perpendicular vectors

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