The probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
Given a fair dice and tossing a fair coin sixteen times.
We have to find the probability that the total number of heads in all the coin tosses equals 12.
The probability lies between 0 and 1.
Probabiltiy of coming head when the coin is tossed 1 time is 0.5 and probability of coming tails is also 0.5.
Let X shows the sum of heads while tossing.
P(X=12)=?
We can find the probability using binomial theorem.
=
We have to toss sixteen times and out of 16 times we need head 12 times.
=16!/12!4!*0.00024*0.0625
=1820*0.000015
=0.0273
Hence the probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
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The formula for a circle is above along with the answer.
Answer:
+ 11m - 11
Step-by-step explanation:
6m+(m-2)(m+7)+3 = 6m + [ m*m - 14 -2m + 7m] + 3
= 6m + mm - 14 + 5m + 3
= mm + 11m - 11
6m+(m-2)(m+7)+3 =
+ 11m - 11
Answer:
x = 12
Step-by-step explanation:
set up a proportion:
<u> 24 </u> = <u> 32 </u>
33 32+x
24(32 + x) = 32(33)
768 + 24x = 1056
24x = 288
x = 12
Answer:
A
Step-by-step explanation:
For b, the constant term is 3, not -3. B is incorrect.
For c, when the brackets are removed using foil, -3 * - 3 = 9. C is incorrect.
For d, There is no reduction, alteration or math procedure that you can use that will make the constant term anything but 9. The answer is not D.
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That means you are left with A which must be right or the question isn't. Turns our that A is the answer -3 * 1 = - 3