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Oxana [17]
3 years ago
15

Ajar contains "x" black and "y" white balls. What is the probability that a random draw is black?

Mathematics
2 answers:
Levart [38]3 years ago
8 0

Answer:

Step-by-step explanation:

favorable events=x

total number of events=x+y

P=(favorable events)/(total number of events)=x/(x+y)

lubasha [3.4K]3 years ago
6 0
If there are ‘x’ black balls and ‘y’ white balls, then the total number in the jar must be x + y.
Therefore, the probability of picking a black ball is the amount of black balls there are divided by the total, which is x/(x+y)

I hope this helps!
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Given
Present investment, P = 22000
APR, r = 0.0525
compounding time = 10 years
Future amount, A 

A. compounded annually
n=10*1=10
i=r=0.0525
A=P(1+i)^n
=22000(1+0.0525)^10
=36698.11

B. compounded quarterly
n=10*4=40
i=r/4=0.0525/4
A=P(1+i)^n
=22000*(1+0.0525/4)^40
=37063.29


Therefore, by compounding quarterly, she will get, at the end of 10 years investment, an additional amount of
37063.29-36698.11
=$365.18

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sashaice [31]
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5 0
3 years ago
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Bond [772]

Answer:

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Step-by-step explanation:

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Hope this helps :)

7 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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