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ZanzabumX [31]
3 years ago
8

Which factor does not influence the rate of a chemical reaction

Chemistry
1 answer:
KonstantinChe [14]3 years ago
5 0
<span>Factors that influence the reaction rates of chemical reactions include the concentration of reactants, temperature, the physical state of reactants and their dispersion, the solvent, and the presence of a catalyst.</span>
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What is the difference between a mixture and a compound? (need an easy two sentence answer (able to explain it to a 8 your old).
lina2011 [118]
<span> A </span>mixture<span> is made from </span>two<span> or more substances that are chemically unlike</span><span> and are not chemically joined. A </span>compound<span> is a substance formed when </span>two<span> or more elements chemically react with each other to ... substances because no new substance is formed, therefore they do not </span>have<span> any fixed properties.</span>
6 0
3 years ago
The average strength of a hydrogen bond is approximately what percent of the average strength of a covalent bond?
lozanna [386]

<span>Hydrogen bonds are approximately 5% of the bond strength of covalent bonds, for example (C-C or C-H bonds).
Hydrogen bonds strength in water is approximately 20 kJ/mol, strenght of carbon-carbon bond is approximately 350 kJ/mol and strengh of carbon-hydrogen bond is approximately 340 kJ/mol.
20 kJ/350 kJ = 0,057 = 5,7 %.</span>

8 0
3 years ago
Which statement is true about a pseudoscientific?​
Alex17521 [72]

Answer:

Wereare they answer choices

Explanation:

7 0
3 years ago
Read 2 more answers
A sample of (NH4)2SO4 contains 0.750 mole. what is the mass of the sample​
steposvetlana [31]
The answer is 99.10.
5 0
2 years ago
What is the concentration in molarity of S2O32- (aq) in a solution prepared by mixing 150 mLmL of 0.149 MM Na2S2O3 (aq) with eno
Artist 52 [7]

Answer:

0.0890 M

Explanation:

Since the concentration of KCl is irrelevant in this case, the concentration of Na2S2O3 can be determined using a simple dilution equation:

C1V1 = C2V2, where C1 = 0.149 M, V1 = 150 mL, V2 = 250 mL

C2 = 0.149 x 150/250

                    = 0.089 M

To determine the concentration of  S2O32- (aq), consider the equation:

Na_2S_2O_3  => 2Na^+_{(aq)} + S_2O^2^-_3_{(aq)}

The concentration of Na2S2O3 and S2O32- (aq) is 1:1

Hence, the concentration in molarity of S2O32- (aq) is 0.089 M.

To 3 significant figures = 0.0890 M

7 0
3 years ago
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