Answer:February 29 is a date that usually occurs every four years, and is called leap day. This day is added to the calendar in leap years as a corrective measure, because the Earth does not orbit the sun in precisely 365 days.
Explanation: brainlest plz
C
Atomic radius is the distance between the center of the nucleus to the outermost orbital shell of the atom. Assume the atom is like a football stadium and the nucleus of the atom is a ball placed at the center of the pitch. The atomic radius is from the center of the ball to the edge of the football stadium.
Explanation:
This atomic radius decreases from left to right of a periodic table because of increases in protons in the nucleus along the periodic table. This increased proton count has a higher attractive force on the electron orbitals of the atom. This decreases the atomic radius
The atomic radius of atoms down a column of the periodic table increase because an extra orbital shell is added to the atoms with every period down the column.
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Answer:
Minimum time = 1.95x10^-4 s
Number of pulses = 5128.21 pulses/s
Explanation:
We have the speed of sound waves through human tissue with a value of 1540 m/s, to calculate the time it takes for the pulse to travel a distance of 30 cm (since the pulse will first travel a distance of 15 cm and then it will return another 15 cm to be detected by the equipment), therefore, the time between the two pulses will be equal to:
tminimum = 0.30 m/1540 m/s = 1.95x10^-4 s
To calculate the number of pulses, one second must be divided over the minimum time between the two pulses, as follows:
npulses = 1 s/1.95x10^-4 s = 5128.21 pulses/s
The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C
<h3>
What does Orbital speed depend on ?</h3>
The speed of an object travelling around a circle depends on two quantities namely;
- Its distance from the center of the circle.
Given that an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)
The given parameters are:
- The mass of Saturn = 5.68 x 10^26 kg
- The orbital radius = 3.00 x 105 km
- G = 6.67 × 10-11 N·m2/kg2
Let us first calculate the gravitational field strength on the Saturn.
g = GM/r²
Substitute all the necessary parameters and convert km to m
g = (6.67 × 
× 5.68 × 
) ÷ (300000 × 1000)²
g = 3.79 × 
÷ 9 ×
g = 0.421 m/s²
The orbital speed will be
V² = gr
V² = 0.4211 × 300000 × 1000
V² = 126333333.3
V = √126333333.3
V = 11239.8 m/s
Convert it to Km/s by dividing the answer by 1000
V = 11239.8/1000
V = 11.2 Km/s
Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s
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<span>
The needle of a compass will always lies along the magnetic
field lines of the earth.
A magnetic declination at a point on the earth’s surface
equal to zero implies that
the horizontal component of the earth’s magnetic field line
at that specific point lies along
the line of the north-south magnetic poles. </span>
The presence of a
current-carrying wire creates an additional <span>
magnetic field that combines with the earth’s magnetic field.
Since magnetic
<span>fields are vector quantities, therefore the magnetic field of
the earth and the magnetic field of the vertical wire must be
combined vectorially. </span></span>
<span>
Where:</span>
B1 = magnetic field of
the earth along the x-axis = 0.45 × 10 ⁻ ⁴ T
B2 = magnetic field due to
the straight vertical wire along the y-axis
We can calculate for B2
using Amperes Law:
B2 = μ₀ i / [ 2 π R ]
B2 = [ 4π × 10 ⁻ ⁷ T • m / A ] ( 36 A ) / [ 2 π (0.21 m ) ] <span>
B2 = 5.97 × 10 ⁻ ⁵ T = 0.60 × 10 ⁻ ⁴ T </span>
The angle can be
calculated using tan function:<span>
tan θ = y / x = B₂ / B₁ = 0.60 × 10 ⁻ ⁴ T / 0.45 × 10 ⁻ ⁴ T <span>
tan θ = 1.326</span></span>
θ = 53°
<span>
<span>The compass needle points along the direction of 53° west of
north.</span></span>
