Answer:
D. Checking to see if the brake fluid is contaminated
Explanation:
The answer, using an indicator to measure the hydrogen ion concentration of a solution, is correct
(a) This is a freefall problem in disguise - when the ball returns to its original position, it will be going at the same speed but in the opposite direction. So the ball's final velocity is the negative of its initial velocity.
Recall that

We have
, so that

(b) The speed of the ball at the start and at the end of the roll are the same 8 m/s, so the average speed is also 8 m/s.
(c) The ball's average velocity is 0. Average velocity is given by
, and we know that
.
(d) The position of the ball
at time
is given by

Take the starting position to be the origin,
. Then after 6 seconds,

so the ball is 42 m away from where it started.
We're not asked to say in which direction it's moving at this point, but just out of curiosity we can determine that too:

Since the velocity is positive, the ball is still moving up the incline.
The frequency of a wave becomes higher due to the object moving at a fast pace coming towards you with shorter wavelengths (depending on the speed) aka the Doppler Effect.
Hope this helps
Answer:
a

b

Explanation:
From the question we are told that
The current is 
The length of one side of the square 
The separation between the plate is 
Generally electric flux is mathematically represented as

differentiating both sides with respect to t is

=> 
Here
is the permitivity of free space with value

=> 
=> 
Generally the displacement current between the plates in A

=> 