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3 years ago

6

How to calculate kinetic energy ? (physics/physical science)

1 answer:

Vladimir79 [104]3 years ago

7 0

Kinetic energy is equal to half of an objects mass multiplied by the velocity squared.

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Place the following into scientific notation...(.000635)<br> *

AleksAgata [21]

6.35x10^-4 OR 6.3x10-4 (if only one decimal number is allowed)

6 0

3 years ago

In the flow past a compression corner, the upstream Mach number and pressure are 3.5 and 1 atm, respectively. Downstream of the

yulyashka [42]

Answer:

$\theta=23.7^{\circ}$

Explanation:

The ratio of pressure 2 to 1 us 5.48/1= 5.48 rounded off as 5.5.

Referring to table A.2 of modern compressible flow then $M_{\beta_1}=2.2$

Also

$M_{\beta_1}=M_1 sin \beta$ and making $sin\beta$ the subject of the formula then

$sin\beta=\frac {2.2}{3.5}\\\beta=38.94^{\circ}$

Making reference to $\theta-\beta-M$ diagram then

$\theta=23.7^{\circ}$

4 0

3 years ago

What type of force pulls in two opposite directions?

torisob [31]

Tensional forces which is associated with normal faults

7 0

3 years ago

Read 2 more answers

How to find out the heat capacity of a material?

DochEvi [55]

$\huge\underline{\underline{\boxed{\mathbb {EXPLANATION}}}}$

The heat capacity is given by the expression:

$\longrightarrow \sf{\triangle Q= m \triangle C \triangle T}$

$\longrightarrow \sf{Q= \: Heat}$

$\longrightarrow \sf{M= \: Mass}$

$\longrightarrow \sf{C= \: Specific \: Heat}$

$\longrightarrow \sf{T= \: Temperature}$

$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

$\leadsto$ When the $\bm{heat}$ is measured in the calorimeter, we obtain a value, and since we know the mass of the material and we control the change in $\bm{temperature}$ , we can then determine the specific heat "C" by simply remplazing in the expression.

5 0

1 year ago

The record time for a Tour de France cyclist to ascend the 1100-mm-high Alpe d'Huez is 37.5 minmin. The rider and his bike had a

katen-ka-za [31]

Answer:

1945.6 W

Explanation:

We are given that

Height,h=1100 m

Time,t=37.5 min= $37.5\times 60=2250 s$

1 min=60 s

Mass,m=65 kg

Power,P=700 W

We have to find the his total metabolic power.

Power,= $P'=\frac{W}{t}=\frac{mgh}{t}=\frac{65\times 9.8\times 1100}{2250}=311.4 W$

Where $g=9.8m/s^2$

Efficiency =25%

Therefore,Power,P'= $\frac{311.4}{0.25}=1245.6 W$

Total metabolic power=P+P'=700+1245.6=1945.6 W

7 0

3 years ago