A dockworker applies a constant horizontal force of 73.0 N to a block of ice on a smooth horizontal floor. The frictional force
is negligible. The block starts from rest and moves a distance 13.0 m in a time 4.50 s.(a)What is the mass of the block of ice?(b)If the worker stops pushing at the end of 4.50 s, how far does the block move in the next 4.20s ? -
1 answer:
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a) The distance of the image from the mirror is 15 cm
b) The size of the image is -2 cm (inverted)
Explanation:
a)
We can solve this first part of the problem by applying the mirror equation:
where
f is the focal length
p is the distance of the object from the mirror
q is the distance of the image from the mirror
For a mirror, the focal length is half the radius of curvature, R:
For this mirror, R = 20 cm, so its focal length is
(positive for a concave mirror)
Here we also know:
p = 30 cm is the distance of the object from the mirror
So, by applying the equation, we can find q:
b)
We can solve this part by using the magnification equation:
where
y' is the size of the image
y is the size of the object
q is the distance of the image from the mirror
p is the distance of the object from the mirror
Here we have:
q = 15 cm
p = 30 cm
y = 4 cm
Solving for y', we find the size of the image:
and the negative sign means that the image is inverted.
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The resultant speed of the plane is (3) 226 m/s
Why?
We can calculate the resultant speed of the plane by using the Pythagorean Theorem since both speeds are perpendicular (forming a right triangle).
So, calculating we have:
Hence, we have that the resultant speed of the plane is (3) 226 m/s
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