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3 years ago

Which is true of high resistance wires?

Physics

1 answer:

miss Akunina [59]3 years ago

4 0

B.The shorter a wire is, the higher the resistance will be

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A football is kicked from ground level with an initial velocity of 23.6 m/s at angle of 57.5° above the horizontal. How long, in

aniked [119]

Answer:

6 seconds is the best answer

3 0

2 years ago

A weather balloon has a volume of 90.0 l when it is released from sea level. What

frozen [14]

The final atmospheric pressure is $5.19\cdot 10^4 Pa$

Explanation:

Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,

$pV=const.$

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

$p_1 V_1 = p_2 V_2$

where in our problem we have:

$p_1= 1.03\cdot 10^5 Pa$ is the initial pressure (the atmospheric pressure at sea level)

$V_1 = 90.0 L$ is the initial volume

$p_2$ is the final pressure

$V_2 = 175.0 L$ is the final volume

Solving the equation for p2, we find the final pressure:

$p_2 = \frac{p_1 V_1}{V_2}=\frac{(1.01\cdot 10^5)(90.0)}{175.0}=5.19\cdot 10^4 Pa$

Learn more about ideal gases:

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3 0

2 years ago

A 2000 N net force will give a car with some amount of mass an acceleration of 4 m/s2

hammer [34]

Answer:

2m/s²

Explanation:

Given parameters:

Net force on the car = 2000N

Acceleration = 4m/s²

Unknown:

Acceleration of a car twice the mass = ?

Solution:

Let us first find the mass of the car;

Force = mass x acceleration

Mass = $\frac{Force }{acceleration}$

Mass = $\frac{2000}{4}$ = 500kg

Now,

whose mass is twice that of the car

Mass of the new car = 2 x 500 = 1000kg

So;

Acceleration = $\frac{Net force }{mass}$

Acceleration = $\frac{2000}{1000}$ = 2m/s²

3 0

2 years ago

At a certain place, Earth's magnetic field has magnitude B =0.703 gauss and is inclined downward at an angle of 75.4° to the hor

Irina18 [472]

Answer:

The charge flows in coulombs is

$dq=1.843x10^{-5}C$

Explanation:

The current magnitude of current is given by the resistance and the induced Emf as:

$I=N*\frac{dF}{Rdt}$

$\frac{dq}{dt}=\frac{dF}{Rdt}=dq=N*\frac{dF}{R}$

$dq=\frac{N*\beta*A*(Cos(\alpha_f)-Cos(\alpha_i}{R}$

$N=1300$ , $\beta=0.703$ , $A=\pi*r^2=\pi*0.10^2=0.01\pi m^2$ , $R=99.4+202=301.4$ Ω

$\alpha_f=14.6$ , $\alpha_i=165.4$

Replacing :

$dq=\frac{1300*0.703x10^{-4}*0.01\pi*(0.9667-(-0.9667))}{202+99.4}$

$dq=1.843x10^{-5}C$

5 0

3 years ago

1 Write 7 next to the statements that are true.

Grace [21]

Answer: The pressure in a liquid dec reaches with depth. F

The pressure in a liquid increases with depth.

The upthrust on an object is larger when it is deeper in a pool. 7

The bottom of a dam is thinner than the top of a dam. F

The bottom of a dam is thicker than the top of a dam.

The pressure is bigger at the bottom of a lake because of the weight of water above it. 7

I think these are the answers.

7 0

3 years ago