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3 years ago

9

2. Which of the following is Not true about the noble gases? a. They have completely filled energy levels. b. They have weak int

ermolecular forces. c. They do not bond with other elements in nature. d. They have boiling points above room temperature.

1 answer:

yanalaym [24]3 years ago

3 0

C because Noble gasses typically do not create chemical bonds.

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A cart is pushed ahead for 3.5 s with a force of 360 N. Determine the change in momentum of the cart.

Katyanochek1 [597]

It is 356.5 just subtracts because it’s opposite

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3 years ago

Which of the following statements is not true?

djyliett [7]

Answer:

Explanation:

1 ) Average power supplied to an inductor is zero because the phase difference of potential and current is π / 2 .

So it is a wrong statement .

2 ) Step up transformer increases the voltage . At high voltage , lesser current is required to transport electrical energy . When current is reduced , the loss of energy due to heating effect is reduced .

3 ) voltage and current are in phase in resistance in ac .

3 ) RMS stands for Root Mean Square .

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4 years ago

A student whirls a rubber stopper attached to a string in a horizontal circle above her head. If the radius of the stopper in ci

algol13

Answer:

$v = 12.57 m/s$

Explanation:

As we know that the radius of the circular motion is given as

$R = 50.00 cm$

time period of the motion is given as

$T = 0.2500 s$

now we know that it is moving with uniform speed

so it is given as

$v = \frac{2\pi R}{T}$

now plug in all data

$v = \frac{2\pi(0.50)}{0.25}$

$v = 12.57 m/s$

7 0

3 years ago

Two points charge of 4\mu C and 2\mu C are placed at theopposite corners of a rectangle. What is the potential difference Va- Vb

bulgar [2K]

Answer:

$Va-Vb=168KV$

Explanation:

From the question we are told that

Two points charge of 4\mu C and 2\mu C

Generally we find the Va and Vb individually to find there difference

Given a rectangle with two equal sides each,Assume lengths for bot sides

Length L=0.3

Breath B=0.4

Diagonal D= $\sqrt{0.3^2+0.4^2} =0.5$

at opposite sides

Mathematically Va can represented as

$Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )$

$Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )$

$Va =9*10^9(0.00001333333-0.000004} )$

$Va =84000V$

$Va =84KV$

Mathematically Vb is represented as

$Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )$

$Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )$

$Va =9*10^9(-0.00001333333+0.000004} )$

$Va =-84000V$

$Va =-84KV$

Therefore

$Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV$

7 0

3 years ago

tekilochka [14]

The answer is 25.37 hope this helps

5 0

3 years ago