Ask question

Ask question

All categories

3 years ago

12

Generators use the magnetic field of which of the following to produce an electric current?

1 answer:

STatiana [176]3 years ago

5 0

<span>Generators use the magnetic field of "Permanent Magnets"

In short, Your Answer would be Option D

Hope this helps!</span>

You might be interested in

How many volts would it take to push 1 amp through a resistance of 1 ohm?

ELEN [110]

V=I x R so V= 1 x 1 =1V

5 0

2 years ago

Read 2 more answers

I NEED THIS FAST

Novay_Z [31]

I think it is b , that what I would i pick

7 0

3 years ago

All of the following are shaped by learned behavior except __________. A. shyness B. blinking C. biting one’s nails D. angry res

Dvinal [7]

Blinking, that’s an involuntary behavior

7 0

2 years ago

Read 2 more answers

HELP PLZ!!!!!<br> Why do things get classified as"hot" or "cold"?

atroni [7]

Answer:

Heat flows from higher to lower temperature. So when you keep hot things in normal temperature, the heat from hot object transfers to the environment until they are both on the same level. Same happens when a cold object is kept in normal room temperature, the heat from the environment transfers to the cold object until they are both equal. its all about achieving the equilibrium in a system

5 0

2 years ago

A golf ball is dropped from rest from a height of 9.50m. It hits the pavement, then bounces back up, rising just 5.70m before fa

marta [7]

Answer:

Explanation:

Given

height from which ball is dropped $h_1=9.5\ m$

and it rises to a height of $h_2=5.7\ m$

A person caught the ball in mid-way i.e. at a height of $h_0=1.2\ m$ from pavement

time taken to reach the bottom is given by

$y=ut+\frac{1}{2}at^2$

where y=displacement

u=initial velocity

a=acceleration

t=time

here initial velocity is zero i.e.

$h_1=0+\frac{1}{2}gt_1^2$

$t_1=\sqrt{\frac{2h_1}{g}}$

Similarly to reach of height $h_2$ time taken is $t_2$

$t_2=\sqrt{\frac{2h_2}{g}}$

The ball is caught in mid-way i.e. ball travel a distance of $h_3=5.7-1.2=4.5\ m$

time taken is $t_3=\sqrt{\frac{2h_3}{g}}$

total time taken $t=t_1+t_2+t_3$

$t=\sqrt{\frac{2h_1}{g}}+\sqrt{\frac{2h_2}{g}}+\sqrt{\frac{2h_3}{g}}$

$t=\sqrt{\frac{2\cdot 9.5}{9.8}}+\sqrt{\frac{2\cdot 5.7}{9.8}}+\sqrt{\frac{2\cdot 4.5}{9.8}}$

$t=3.429\ s$

total time =3.429 s

4 0

3 years ago