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Liono4ka [1.6K]

3 years ago

5

What are 2 different ways you can improve your endurance, muscular strength, flexibility, and body composition before your next

physical fitness test?

1 answer:

lidiya [134]3 years ago

3 0

You can improve by doing aerobic exercises and stretching all muscle groups daily. A healthy diet balanced with exercise help your body composition.

You might be interested in

5. Based on the data collected by the students, what is the tangential velocity of

malfutka [58]

The tangential velocity of the ball is 0.63 m/s.

<h3>What is tangential speed?</h3>

Tangential speed is the linear component of the speed of any object moving along a circular path.

v = ωr

where;

v is the tangential speed
ω is the angular speed (rad/s)
r is the radius of the circle

At a given radius of the circle = 0.3 m

Let the number of revolution per min = 20 rev/min

$\omega = 20 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} = 2.1 \ rad/s$

v = ωr

v = 2.1 x 0.3

v = 0.63 m/s

Thus, the tangential velocity of the ball is 0.63 m/s.

Learn more about tangential velocity here: brainly.com/question/25780931

8 0

2 years ago

A 0.5 kg mass moves 40 centimeters up the incline shown in the figure below. The vertical height of the incline is 7 centimeters

Tanya [424]

Answer:

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

Explanation:

We must remember in this case that change in the potential energy is entirely represented by the change in the gravitational potential energy. From Work-Energy Theorem and definition of work we get that:

$U_{g}= m\cdot g\cdot \Delta y$

Where:

$U_{g}$ - Gravitational potential energy, measured in Joules.

$m$ - Mass, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

$\Delta y$ - Change in vertical height, measured in meters.

This work is the energy needed to counteract effects of gravity at given vertical displacement.

If we know that $m = 0.5\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ and $\Delta y = 0.07\,m$ , the change in the potential energy of the mass as it goes up the incline is:

$U_{g} = (0.5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.07\,m)$

$U_{g} = 0.343\,J$

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

5 0

3 years ago

Steam at 4 MPa and 400C enters a nozzle steadily with a velocity of 60 m/s, and it leaves at 2 MPa and 300C. The inlet area of

frez [133]

Answer:

(A) 4.09 kg/s

(B) 589.9 m/s

(C) 0.0008707 m^{3} = 8.71 cm^{2}

Explanation:

inlet pressure of steam (P1) = 4 MPa

inlet temperature of steam (T1) = 400 degree celcius

inlet velocity (V1) = 60 m/s

outlet pressure (P2) = 2 MPa

outlet temperature (T2) = 300 degree celcius

inlet area (A1) = 50 cm^{2} = 0.005 m^{2}

rate of heat loss (Q) = 75 kJ/s

(A) mass flow rate (m) = \frac{A1 x V1}{α1}

where the initial specific volume (α1) for the given temperature and pressure is gotten from tables A-6 = 0.07343 m^3/kg

m = \frac{0.005 x 60}{0.07343}

m = 4.09 kg/s

(B) we can get the outlet velocity using the energy balance equation

E in = E out

m(h1 + \frac{(V1)^{2}}{2}) = m(h2 + \frac{(V2)^{2}}{2})

V2 = $\sqrt{2(h1 - h2) +(V1)^{2} - 2\frac{Q}{m}$

where h1 and h2 are the enthalpies and are gotten from table A-6

V2 = $\sqrt{2 x 1000 x(3214.5 - 3024.2) +(60)^{2} - 2\frac{75 x 1000}{4.09}$

V2 = 589.9 m/s

(C) the outlet area is gotten from mass flow rate (m) = \frac{A2 x V2}{α}

A2 = (α2 x m) / V2

where the initial specific volume (α2) for the given temperature and pressure is gotten from tables A-6 = 0.12552 m^3/kg

A2 = (0.12552 x 4.09) / 589.5 = 0.0008707 m^{3} = 8.71 cm^{2}

4 0

3 years ago

Solar cell A produces 100 joules of energy, when a light source is shown on it for 3 minutes. Solar cell B produces 200 joules o

ella [17]

Answer: (B). Solar cell B, because it generates more power.

Explanation:

Given that,

For solar cell A

Energy = 100 Joules

Time = 3 minutes = 180 sec

Power of cell A

Power = Energy/Time

$P = \dfrac{100}{180}\ Watt$

$P = 0.55\ Watt$

For solar cell B

Energy = 200 joules

Time = 5 minutes = 300 sec

Power of cell B

Power = Energy/Time

$P = \dfrac{200}{300}\ watt$

$P = 0.66\ Watt$

Hence, Solar cell B, because it generates more power.

3 0

3 years ago

Read 2 more answers

Two objects, one having twice the mass of the other, are initially at rest. Two forces, one twice as big as the other, act on th

Elodia [21]

<em><u>Note: There is no image to take as a reference, so I'm assuming F2 directed to the right and F1 to the left, and F2=2F1</u></em>

Answer:

$\displaystyle a=\frac{F}{3M}$

<em>to the right</em>

Explanation:

<u>Net Force</u>

When several forces are applied to a particle or a system of particles, the net force is the sum of them all, considering each force as a vector. As for the second Newton's law, the total force equals the product of the mass by the acceleration of the system:

$\vec F_n=m\cdot \vec a$

If the net force is zero, then the system of particles keeps at rest or at a constant velocity.

The system of particles described in the question consists of two objects of masses m1=M and m2, where

$m_2=2m_1=2M$

Two forces F1=F and F2 act individually on each object in opposite directions and

$F_2=2F_1=2F$

We don't get to see any image to know where the forces are applied to, so we'll assume F2 to the right and F1 to the left.

The net force of the system of particles is

$F_n=2F-F=F$

The mass of the system is

$m_t=m_1+m_2=3M$

Thus, the acceleration of the center of mass of the system is

$\displaystyle a=\frac{F}{3M}$

Since F2 is greater than F1, the direction of the acceleration is to the right.

Note: If the forces were opposite than assumed, the acceleration would be to the left

6 0

3 years ago