Answer: D=4.35g/L
Explanation:
The formula for density is
. M is mass in grams and V is volume in liters.
Since we are give pressure and temperature, we can use the ideal gas law to find moles/volume. FInding moles/volume would give us the base for density. All we would have to do is convert moles to grams.
Ideal Gas Law: PV=nRT
![\frac{n}{V} =\frac{P}{RT}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7BV%7D%20%3D%5Cfrac%7BP%7D%7BRT%7D)
![\frac{n}{V}=\frac{1.50 atm}{(0.08206Latm/Kmol)(25+274.15K)}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7BV%7D%3D%5Cfrac%7B1.50%20atm%7D%7B%280.08206Latm%2FKmol%29%2825%2B274.15K%29%7D)
![\frac{n}{V} =\frac{0.061309mol}{L}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7BV%7D%20%3D%5Cfrac%7B0.061309mol%7D%7BL%7D)
Now that we have moles, we can use molar mass of chlorine gas to find grams.
![0.061309mol*\frac{71.0g}{mol} =4.3529g](https://tex.z-dn.net/?f=0.061309mol%2A%5Cfrac%7B71.0g%7D%7Bmol%7D%20%3D4.3529g)
With our grams, we can find our density.
![D=\frac{4.3529g}{L}](https://tex.z-dn.net/?f=D%3D%5Cfrac%7B4.3529g%7D%7BL%7D)
We need correct significant figures so our density is:
![D=\frac{4.35g}{L}](https://tex.z-dn.net/?f=D%3D%5Cfrac%7B4.35g%7D%7BL%7D)
B) chemical bond i believe is the correct answer
Answer:
Increase the pressure of the gas
Explanation:
According to the Pressure law, for a fixed mass of gas, at a constant volume (V), the pressure (P) is directly proportional to the absolute temperature (T).
From the kinetic molecular theory, gases are composed of particles which are in constant motion, colliding with themselves as well as with the walls of their container.
When the temperature of these gas molecules is increased, the molecules acquire more kinetic energy and the rate of collisions increases. Since the container cannot expand, the increase in pressure is due to the increase in collisions between the molecules of the gas as well as with the walls of their container.
<span>C + O2 → CO2
(8,376,726 tons) x (0.80) / (12.01078 g C/mol) x (1 mol CO2/ 1 mol C) x
(44.00964 g CO2/mol) = 24,555,054 tons CO2</span>