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Sonja [21]
3 years ago
5

A certain mountain road is inclined 3.1° with respect to the horizon. what is the change in altitude of the car as a result of i

ts traveling 2.90 km along the road?
Physics
1 answer:
BigorU [14]3 years ago
7 0
Given:\\ \alpha =3.1^\circ\\l=2.90km\\\\Find:\\h=?\\\\Solution:\\\\h=l\sin\alpha \\\\h=2.90km\cdot \sin 3.1^\circ=2.90km\cdot 0.054=0,1566km=156.6m
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a girl pushes a cart to the left with a 100-N force. A boy pushes it to the right with a 50-N force. what is the net force exert
NNADVOKAT [17]

Answer:

50 to the left

Explanation:

150-100: 50 to the left

3 0
2 years ago
Two trains leave the station at the same time, one heading east and the other west. the eastbound train travels at 95 miles per
marissa [1.9K]
The east bound train travels at a speed of 95 mile per hour and the west bound train at 75 miles per hour.
Assuming eastbound train will cover distance x then the west bound train will cover distance 272-x .
Therefore, since time taken will be the same then; x/95 = (272-x)/75
          = 75x = 95 (272-x)
          = 75x = 25840 - 95x
          = 170 x= 25840
                     x = 152 miles
Thus time taken will either be x/95 or (272-x)/75
           = 152/95
           = 1.6 hours or 1 hour 36 minutes
6 0
3 years ago
Which of the following affects the gravitational attraction between two objects? A. The mass of the objects. B. The distance bet
Ede4ka [16]

Answer:

a

Explanation:

the mass of the object

5 0
3 years ago
Calculate the kinetic energy of a 1000 kg car traveling at 30 m/s, a typical speed on a<br> highway.
Arte-miy333 [17]

The kinetic energy of the car is 4.5\cdot 10^5 J

Explanation:

The kinetic energy of an object is the energy possessed by the object due its motion. It is given by

E_k = \frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the car in this problem, we have:

m = 1000 kg is its mass

v = 30 m/s is its speed

Substituting into the equation, we find the kinetic energy of the car:

E_k = \frac{1}{2}(1000)(30)^2=4.5\cdot 10^5 J

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

7 0
3 years ago
Calculate the potential energy of 20kg object sitting on a 8meter ledge
trapecia [35]

Answer:

potential energy=mgh (weight × height)

m=20kg

g=9.8m/s2

h=8

20×9.8×8=1568

The potential energy is 1568J

5 0
3 years ago
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