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Tamiku [17]
1 year ago
11

The magnitude of the force associated with the gravitational field is constant and has a value f. A particle is launched from po

int b with an initial velocity and reaches point a having gained u0 joules of kinetic energy. A resistive force field is now set up such that it is directed opposite the gravitational field with a force of constant magnitude 12f. A particle is again launched from point b. How much kinetic energy will the particle gain as it moves from point b to point a?.
Physics
1 answer:
hodyreva [135]1 year ago
6 0

The particle will have an energy of 12U0. A particle travels at an initial velocity from point B to point A, gaining U0 joules of kinetic energy along the way. The constant force at this point is equal to 12F.

<h3>Does 9.8 represent gravity?</h3>

The acceleration which gravity gives to objects falling freely serves as a gauge of its strength. The gravity's acceleration at Earth's surface is approximately 9.8 meters (32 feet) per second every second.

<h3>What is a good illustration of gravity?</h3>

The following are a few instances of the power of gravity: the energy holding the gases inside the sun. the power behind a ball's descent after being thrown into the air. the force that makes an automobile coast down even when the gas is not depressed.

To know more about Gravitational visit:

brainly.com/question/3009841

#SPJ4

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You repeated a measurement 6 times and recorded the time using a stop watch: 5.8s, 4.6s, 4.8s, 5.1s, 4.3s, 4.6s. What average va
iVinArrow [24]

Answer and Explanation

Arranging the measured values in increasing order;

4.3s, 4.6s, 4.6s, 4.8s, 5.1s, 5.8s

The two outliers are obviously 4.3s and 5.8s; An outlier is a value in a statistical sample which does not fit a pattern that describes most other data point. Outliers make the average value complicated. So, it is usually better for data to be precise with data points spreading out around a small area.

So, the mean is the average of the four remaining data points after removing the outliers.

Mean = (4.6 + 4.6 + 4.8 + 5.1)/4

Mean = 4.775s

So, the value recorded should be 4.775s, 4.78s or 4.8s depending on the number of decimal places allowed.

QED!

8 0
4 years ago
During the motion of the slinky in a transverse wave, what do the particles of the slinky coil do?
Mazyrski [523]

Answer:

C.) The slinky particles move up and down

Explanation:

<u>Transverse Wave</u>-

<em>A wave that has a disturbance perpendicular to the wave motion</em>

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<em>Hello! This is the correct answer! Have a blessed day! :)</em>

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5 0
3 years ago
(a) Calculate the self-inductance (in mH) of a 55.0 cm long, 10.0 cm diameter solenoid having 1000 loops.
DedPeter [7]

Explanation:

(a) We have,

Length of solenoid, l = 55 cm = 0.55 m

Diameter of the solenoid, d = 10 cm

Radius, r = 5 cm = 0.05 m

Number of loops in the solenoid is 1000.

(a) The self inductance in the solenoid is given by :

L=\dfrac{\mu_o N^2A}{l}

A is area

L=\dfrac{4\pi \times 10^{-7}\times (1000)^2\times \pi (0.05)^2}{0.55}\\\\L=0.0179\ H\\\\L=17.9\ mH

(b) The energy stored in the inductor is given by :

E=\dfrac{1}{2}LI^2\\\\E=\dfrac{1}{2}\times 0.0179\times (19.5)^2\\\\E=3.4\ J

Hence, this is the required solution.

4 0
3 years ago
A motor does a total of 480 J of work if 5 s to lift a 12 clock to the top of a ramp. The average power developed by the motor i
marta [7]

Answer:

Power = work / time

P = 480 / 5 = 96W

3 0
2 years ago
Read 2 more answers
A constant amount of charge passes through a conductor. How is current affected if the same amount of charge passes in less time
baherus [9]

Answer:

B. The current increases.

Explanation:

As we know that rate of flow of charge through the conductor is known as electric current

So we have

i = \frac{q}{t}

here we know that charge Q flowing through the conductor is constant while the time in which it passes through it is decreased

so we can say that the ratio of charge and time will increase

so here we have

i = increased

So correct answer will be

B. The current increases.

4 0
3 years ago
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