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Tamiku [17]
1 year ago
11

The magnitude of the force associated with the gravitational field is constant and has a value f. A particle is launched from po

int b with an initial velocity and reaches point a having gained u0 joules of kinetic energy. A resistive force field is now set up such that it is directed opposite the gravitational field with a force of constant magnitude 12f. A particle is again launched from point b. How much kinetic energy will the particle gain as it moves from point b to point a?.
Physics
1 answer:
hodyreva [135]1 year ago
6 0

The particle will have an energy of 12U0. A particle travels at an initial velocity from point B to point A, gaining U0 joules of kinetic energy along the way. The constant force at this point is equal to 12F.

<h3>Does 9.8 represent gravity?</h3>

The acceleration which gravity gives to objects falling freely serves as a gauge of its strength. The gravity's acceleration at Earth's surface is approximately 9.8 meters (32 feet) per second every second.

<h3>What is a good illustration of gravity?</h3>

The following are a few instances of the power of gravity: the energy holding the gases inside the sun. the power behind a ball's descent after being thrown into the air. the force that makes an automobile coast down even when the gas is not depressed.

To know more about Gravitational visit:

brainly.com/question/3009841

#SPJ4

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Answer: It indicates the speed of a object. The steeper the line the greater the speed of the object.

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At what stage of a reaction do atoms have the highest energy?
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3 years ago
If the caffeine concentration in a particular brand of soda is 2.97 mg/oz, 2.97 mg/oz, drinking how many cans of soda would be l
Ray Of Light [21]

Explanation:

The given data is as follows.

     Concentration of caffeine = 2.97 mg/oz

     Number of oz in a can = 12 oz

Therefore, the concentration of caffeine in one can is calculated as follows.

                 = (12 \times 2.97) mg

                 = 35.64 mg

                 = 35.64 \times 10^{-3} g

Since, it is given that lethal dose is 10.0 g. Hence, number of cans are calculated as follows.

     No. of cans = \frac{\text{Lethal dose}}{\text{concentration in one can}}

                         = \frac{10 g}{35.64 \times 10^{-3} g}

                         = 280.58

                         = 281 (approx)

Thus, we can conclude that 281 cans of soda would be lethal.

5 0
3 years ago
A capacitor with air between its plates ischarged to 60 V and then disconnected fromthe battery. When a piece of glass is placed
-BARSIC- [3]

Answer:

       k = 1.30

Explanation:

For this exercise let's write the capacitance in air and with dielectric

air             C₀ = Q / DV

dielectric  C = k Q / DV

They tell us that the capacitor is charged and then the battery is disconnected, therefore the charge stored on the plate remains constant.

                         

therefore the capacitance a changes to the value

           C = k C₀

The voltage in the presence of dielectric must meet the relationship

           ΔV = ΔV₀ / k

           k = ΔV₀ /ΔV

let's calculate

           k = 60/46

           k = 1.30

5 0
2 years ago
Experiment 7 static equilibrium of a rigid body.
Anna007 [38]

The answer is yes. You know this because the table isn't moving or rotating.

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