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Tamiku [17]
1 year ago
11

The magnitude of the force associated with the gravitational field is constant and has a value f. A particle is launched from po

int b with an initial velocity and reaches point a having gained u0 joules of kinetic energy. A resistive force field is now set up such that it is directed opposite the gravitational field with a force of constant magnitude 12f. A particle is again launched from point b. How much kinetic energy will the particle gain as it moves from point b to point a?.
Physics
1 answer:
hodyreva [135]1 year ago
6 0

The particle will have an energy of 12U0. A particle travels at an initial velocity from point B to point A, gaining U0 joules of kinetic energy along the way. The constant force at this point is equal to 12F.

<h3>Does 9.8 represent gravity?</h3>

The acceleration which gravity gives to objects falling freely serves as a gauge of its strength. The gravity's acceleration at Earth's surface is approximately 9.8 meters (32 feet) per second every second.

<h3>What is a good illustration of gravity?</h3>

The following are a few instances of the power of gravity: the energy holding the gases inside the sun. the power behind a ball's descent after being thrown into the air. the force that makes an automobile coast down even when the gas is not depressed.

To know more about Gravitational visit:

brainly.com/question/3009841

#SPJ4

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