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Anon25 [30]
3 years ago
6

A city bus travels six blocks east and eight blocks north east wok is 100 m long is a bus travels as distance and 15 minutes wha

t is the average speed on the bus
Physics
1 answer:
mariarad [96]3 years ago
7 0

Answer:

the average speed on the bus =  1.55 m/s

Explanation:

From the information we are being provided with ;

a city block travels 6 blocks due east

and 8 blocks due north

the length of the individual blocks = 100m

As such their respective distance will be

distance (d) traveled due east direction by bus = 6 × 100 = 600 m

distance (d) traveled towards the north direction by bus = 8 × 100 = 800 m

The total distance covered  = (600+ 800)m

= 1400 m

However, it requires 15 minutes to travel this distance by bus.

Thus,  

the average speed = distance/ time

the average speed on the bus = 1400 m / (15 × 60) s

the average speed on the bus =  1400 m / 900 s

the average speed on the bus =  1.55 m/s

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an object is moving with initial velocity of 5 m/s. After 10 seconds final velocity is 10 m/s. Calculate its acceleration.​
Brut [27]

Answer:

0.5m/s2

Explanation:

acceleration= change in velocity/time taken

= v - u/ t

= 10-5/10

=5/10

= 0.5m/s2

6 0
3 years ago
A pulsar is a rapidly rotating neutron star. The Crab nebula pulsar in the constellation Taurus has a period of 33.5\times 10^{-
joja [24]

Answer:

5.25\cdot 10^{40} kg m^2/s

Explanation:

The angular momentum of the pulsar is given by:

L=m\omega r^2

where

m=2.8\cdot 10^{30} kg is the mass of the pulsar

r = 10.0 km = 1\cdot 10^4 m is the radius

\omega is the angular speed

Given the period of the pulsar, T=33.5\cdot 10^{-3} s, the angular speed is given by

\omega=\frac{2\pi}{T}=\frac{2 \pi}{33.5\cdot 10^{-3}s}=187.5 rad/s

And so, the angular momentum is

L=m\omega r^2=(2.8\cdot 10^{30}kg)(187.5 rad/s)(1\cdot 10^4 m)^2=5.25\cdot 10^{40} kg m^2/s

8 0
3 years ago
Medical x-rays, with a wavelength of about 10^(-10) m, can penetrate completely through your skin.
natulia [17]
Wavelength of X-rays = 10⁻¹⁰ m
Wavelength of UV = 1000 x 10⁻¹⁰
= 10⁻⁷ m
4 0
3 years ago
A flywheel with a radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2. Compu
boyakko [2]

Answer:

0.42 m/s²

Explanation:

r = radius of the flywheel = 0.300 m

w₀ = initial angular speed = 0 rad/s

w = final angular speed = ?

θ = angular displacement = 60 deg = 1.05 rad

α = angular acceleration = 0.6 rad/s²

Using the equation

w² = w₀² + 2 α θ

w² = 0² + 2 (0.6) (1.05)

w = 1.12 rad/s

Tangential acceleration is given as

a_{t} = r α = (0.300) (0.6) = 0.18 m/s²

Radial acceleration is given as

a_{r} = r w² = (0.300) (1.12)² = 0.38 m/s²

Magnitude of resultant acceleration is given as

a = \sqrt{a_{t}^{2} + a_{r}^{2}}

a = \sqrt{0.18^{2} + 0.38^{2}}

a = 0.42 m/s²

8 0
3 years ago
Professional application dr. john paul stapp was u.s. air force officer who studied the effects of extreme deceleration on the h
aleksley [76]
A) Acceleration= (282m/s-0m/s)/5.0s= 56.4m/s^2
b) Deceleration=(0m/s-282m/s)/1.40s=201.4m/s^2 (here we reject negative because deceleration already take into account negative)
c) for the first one the multiple will be 5.76g
for the second one it will be 20.6g
5 0
3 years ago
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