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enot [183]
3 years ago
8

Jonah rode his skateboard 350 meters down a straight road at a constant velocity. He skated

Physics
1 answer:
Marysya12 [62]3 years ago
8 1

Answer:

250 m/min down the road

Explanation:

Velocity is equivalent to speed but it considers the direction of the object. Velocity is also calculated by dividing the distance travelled by time. Therefore, v=\frac {d}{t} where d and t are distance and time respectively. Given that d is given as 350 m and t is 1.4 s then by substitution v=\frac {350}{1.4}=250 m/min and the direction is down the road.

Velocity is 250 m/min down the road

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= 6.0 x 10^-7 m

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The greater the mass of an object, the greater the _____. (fill in question) ​
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A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of
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The magnitude (in N) of the force she must exert on the wrench is 150.1 N.

<h3>Force exerted by the wrench</h3>

The force exerted by the wrench is calculated using torque formula as follows;

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5 0
2 years ago
A 1500 kg car drives around a flat 200-m-diameter circular track at 25m/s. What are the magnitude and direction of the net force
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The correct answer to the question is : 9375 N.

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As per the question, the mass of the car  m = 1500 Kg.

The diametre of the circular track D = 200 m.

Hence, the radius of the circular path R = \frac{D}{2}

                                                                  = \frac{200}{2}\ m

                                                                  = 100 m.

The velocity of the truck v = 25 m/s.

When a body moves in a circular path, the body needs a centripetal force which helps the body stick to the orbit. It acts along the radius and towards the centre.

Hence, the force acting on the car is centripetal force.

The magnitude of the centripetal force is calculated as -

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                                            =  \frac{1500\times (25)^2}{100}\ N

                                            = 9375 N.           [ANS}        

The centripetal force is provided to the car in two ways. It is the friction which provides the necessary centripetal force. Sometimes friction is not sufficient. At that time, the road is banked to some extent which provides the necessary centripetal force.


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