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Nutka1998 [239]
3 years ago
11

Anyone have any good ways of revisiting Or Have any good study notes

Engineering
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

Write all notes in google docs

Explanation:

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Do heavier cars really use more gasoline? Suppose a car is chosen at random. Let x be the weight of the car (in hundreds of poun
Alex17521 [72]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks necessary data to solve. But I have found the similar question on the internet. So, I will be using the data from that question to solve this question for the sack of concept and understanding.

Data Given:

x = 27 , 44 , 32 , 47, 23 , 40, 34, 52

y = 30, 19,  24,  13 , 29,  19,  21,  14

It is given that,

∑x = 299

∑y = 167

∑x^{2} = 11887

∑y^{2} = 3773

We are asked to verify the above values manually in this question.

So,

1. ∑x = 299

Let's verify it:

∑x = 27 + 44 + 32 + 47 + 23 + 40 + 34 + 52

∑x = 299

Yes, it is equal to the given value. Hence, verified.

2. ∑y = 167

Let's verify it:

∑y = 30 + 19 +  24 + 13 + 29 + 19 +  21 +  14

∑y = 169

No, it is not equal to the given value.

3. ∑x^{2} = 11887

Let's verify it:

For this to find,  first we need to square all the value of x individually and then add them together to verify.

∑x^{2} = 27^{2} + 44^{2} + 32^{2} + 47^{2} + 23^{2} + 40^{2} + 34^{2} + 52^{2}

∑x^{2} = 11,887

Yes, it is equal to the given value. Hence, verified.

4. ∑y^{2} = 3773

Let's verify it:

Again, for this we need to find the squares of all the y values and then add them together to verify it.

∑y^{2} = 30^{2} + 19^{2} +  24^{2} + 13^{2} + 29^{2} + 19^{2} +  21^{2} +  14^{2}

∑y^{2}  = 3,845

No, it is not equal to the given value.

4 0
3 years ago
Example – a 100 kW, 60 Hz, 1175 rpm motor is coupled to a flywheel through a gearbox • the kinetic energy of the revolving compo
rjkz [21]

Answer:

1200KJ

Explanation:

The heat dissipated in the rotor while coming down from its running speed to zero, is equal to three times its running kinetic energy.

P (rotor-loss) = 3 x K.E

P = 3 x 300 = 900 KJ

After coming to zero, the motor again goes back to running speed of 1175 rpm but in opposite direction. The KE in this case would be;

KE = 300 KJ

Since it is in opposite direction, it will also add up to rotor loss

P ( rotor loss ) = 900 + 300 = 1200 KJ

7 0
3 years ago
Rope BCA passes through a pulley at point C and supports a crate at point A. Rope segment CD supports the pulley and is attached
djverab [1.8K]

Answer:

363 pounds 32 degrees

Explanation:

Express your answers numerically in pounds and degrees to three significant figures separated by a comma. slader

6 0
3 years ago
Which of the following sentences uses the active voice
MrRa [10]

Answer: Last week, Nate and I counted all the inventory.

Explanation: all other choices are passive voices

this sentence follows a clear subject + verb + object construct that's why it is an active voice. In fact, sentences constructed in the active voice add impact to your writing. but on the other hand With passive voice, the subject is acted upon by the verb.

Ape x

7 0
3 years ago
The pressure rise Ap associated with wind hitting a win- dow of a building can be estimated using the formula Ap-p(12/2), where
Harrizon [31]

Answer:

a. 430.944 pascal

b. 0.0625psi

c. 1.73008inH20

Explanation:

The pressure rise Ap associated with wind hitting a win- dow of a building can be estimated using the formula Ap-p(12/2), where p is density of air and V is the speed of the wind. Apply the grid method to calculate pressure rise for P-1.2 kg/m and V-60 mph. a. Express your answer in pascals. b. Express your answer in pounds-force per square inch (psi). c. Express your answer in inches of water column

checking the dimensional consistency

Dp=\frac{kg}{m^3} (\frac{m^2}{s^2} \\\frac{x}{y} \\\\\frac{kg}{ms^2} \\which s the same as\\ \frac{N}{m^2}

Dp=∈(\frac{v^2}{2} )

convert 1 mile to meter

1mile=1609m

1h=3600s

60mile/h=26.8m/s

slotting intpo the relation

Dp=1.2kg/m^3(\frac{26.8^2}{2} )

430.944kg/(ms^2)

which is the same as 430.944N/m^2

expressing in pascal.

We know that

1 pascal=1 N/m^2

430.944 pascal

2. 1 pascal=0.000145psi

answer=0.0625psi

3.1 pascal=0.00401inH20

answer=430.944*0.0040146

1.73008inH20

5 0
3 years ago
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