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Vadim26 [7]
4 years ago
8

A Charpy V Notch test was conducted for an ASTM A572 Grade 50 bridge steel. The average values of the test results at four diffe

rent test temperatures were found to be
10 ft.lb at 50 degrees F, 15 ft.lb at 0 degrees F, 40 ft.lb at 40 degrees F, 60 ft.lb at 100 degrees F.

The bridge will be located in a region where specifications require a minimum of 25 ft.lb fracture toughness at 30 degrees F for welded fracture-critical members. If the bridge contains a welded flange in a fracture-critical member, does the steel have adequate Charpy V notch fracture toughness? Show your supporting calculations.

Engineering
1 answer:
goldenfox [79]4 years ago
5 0

Answer:

Explanation: see attachment below

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Steam enters a turbine at 120 bar, 508oC. At the exit, the pressure and quality are 50 kPa and 0.912, respectively. Determine th
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The turbine produces <u>955.53 KW</u> power.

Explanation:

Taking the turbine as a system. Applying Law of Conservation of Energy:

m(h₁ - h₂) - Heat Loss = P

where,

m = mass flow rate of steam = 1.31 kg/s

h₁ = enthalpy at state 1 (120 bar and 508°C)

h₂ = enthalpy at state 2 (50 KPa and x = 0.912)

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P = Power generated by turbine = ?

First, we find h₁ from super steam tables:

At,

T = 508°C

P = 120 bar = 12000 KPa = 12 MPa

we find that steam is in super-heated state with enthalpy:

Due to unavailibility of values in chart we approximate the state to 500° C and 12.5 MPa:

h₁ = 3343.6 KJ/kg

Now, for state 2, we have:

P = 50 KPa and x = 0.912

From saturated steam table:

h₂ = hf₂ + x(hfg₂) = 340.54 KJ/kg + (0.912)(2304.7 KJ/kg)

h₂ = 2442.4 KJ/kg

Now, using values in the conservation equation:

(1.31 kg/s)(3343.6 KJ/kg - 2442.4 KJ/kg) - 225 KW = P

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Durante el segundo trimestre de 2001, Tiger Woods fue el golfista que más dinero ganó en el PGATour. Sus ganancias sumaron un to
ehidna [41]

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N = population size (10)

n = random selection (2)

r = number of observations = 7

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f(y) = ( r/y ) ( N - r / n - y ) / ( N /n )

When y = 1

f(1) = ( 7/1 ) ( 10 - 7 / 2 -1 ) / ( 10/2 )

= 7 / 15

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When y = 2

f(2) = ( 7/2 ) ( 10 - 7 / 2 -2 ) / ( 10/2 )

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f(0) = ( 7/0 ) ( 10 - 7 / 2 -0) / ( 10/2 )

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If block A of the pulley system is moving downward at 6 ft&gt;s while block C is moving down at 18 ft&gt;s, determine the relati
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Answer:

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