Rate of production of NO₂ = 0.2 M/s
Rate of production of O₂ = 0.05 M/s
<h3>Further explanation</h3>
Given
The rate of N₂O₅ : 0.1 M/s
Reaction
2N₂O₅⇒4NO₂+O₂
Required
The rate of production of NO₂ and O₂ at the same time point
Solution
Rate of disappearance of N₂O₅ = reaction rate x coefficient of N₂O₅
0.1 M/s=reaction rate x 2
<em>reaction rate = 0.05 M/s</em>
The rate of production of NO₂=
Rate of production of NO₂ = reaction rate x coefficient of NO₂
Rate of production of NO₂ = 0.05 M/s x 4
Rate of production of NO₂ = 0.2 M/s
The rate of production of O₂=
Rate of production of O₂ = reaction rate x coefficient of O₂
Rate of production of O₂ = 0.05 M/s x 1
Rate of production of O₂ = 0.05 M/s
