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Yuki888 [10]
3 years ago
12

How many mols is 1433.6 iron atoms

Chemistry
1 answer:
larisa86 [58]3 years ago
7 0
<span>How many mols is 1433.6 iron atoms? my calculations are 2.380548514178884521</span>

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What does the coefficients in a balanced chemical equation represent​
attashe74 [19]

Answer:

th mol

Explanation:

When you balance an equation, you can refer back to the coefficients when calcuating mol and molar mass from the given information about one reactant to antoher reactant ot product. you use the coeffiecients for mol-mol ratio.

for example. if you are given A +3 B -----> 6C + 5D, and you have 10 mol of A and you have to find how many mols of C with 10 mol of A. then you would ratio it as A: C = 10A: 10C= 10(1): 10(6)= 10:60. so with 10 mol A you can make 60 mol C.

8 0
3 years ago
Convert 3.00 x 10^5 km/sec to miles/hr. (1 mile = 1.609 km)
SVETLANKA909090 [29]

Answer:

3\times 10^5\ \dfrac{km}{s}=6.71\times 10^8\ \text{miles per hour}

Explanation:

In this problem, we need to convert 3\times 10^5\ km/s to miles per hour

We know that,

1 mile = 1.609 km

1 hour = 3600 seconds

3\times 10^5\ \dfrac{km}{s}=3\times 10^5\dfrac{(\dfrac{1}{1.609}\ \text{miles})}{\dfrac{1}{3600}\ \text{hour}}\\\\=6.71\times 10^8\ \text{miles per hour}

Hence, 3\times 10^5\ \dfrac{km}{s}=6.71\times 10^8\ \text{miles per hour}

3 0
4 years ago
What bias conditions must be present for the normal operation of a transistor amplifier? A. The emitter-base junction must be fo
natali 33 [55]
The answer would be A. which says the emitter- base junction must be forward biased, and the collector- base junction must be reverse biased.
8 0
3 years ago
What substance is a combination of different atoms
MrMuchimi
I'm not suree.. is his science?
7 0
4 years ago
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What is the overall cell potential for this redox reaction? Cd + Hg22+ → Cd2+ + 2Hg Given: Cd2+ + 2e− → Cd(s) = –0.40 and Hg22+
Hoochie [10]

Answer:  1.19 V

Explanation:

Standard potential for an electrochemical cell is given by:

E^0{cell} = standard electrode potential =E^0{cathode}-E^0{anode}

The E^0 values have to be reduction potentials.  

Given:

E^o_{Cd^{2+}/Cd}=-0.40V

E^o_{Hg_2^{2+}/Hg}=0.79V

Cd+Hg_2^{2+}\rightarrow Cd^{2+}+2Hg

Cadmium is losing electrons , undergo oxidation and thus act as anode. mercury is gaining electrons, undergo reduction and thus acts as cathode.

E^0{cell} = standard electrode potential =E^0{cathode}-E^0{anode}=0.79-(-0.40)=1.19V

Thus the standard potential for an electrochemical cell with the cell reaction is 1.19 V.

4 0
3 years ago
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