Answer:
Explanation:
When the two dissimilar bodies rubbed together, they the both of the bodies becomes charged. One of the body gets positive charge and the other body gets negative charge.
the positively charged body loses some electrons and the negatively charged body gains some electrons.
According to the properties of charge when the plastic rod is rubbed with the fur, the plastic rod has a tendency to get the negative charge and the fur has a tendency to get positive charge.
So,
When we rub a plastic rod with a piece of fur, electrons--------------transfer from fur----------------to the -------plastic-----. In the result charging fur with -positive-----------charge and plastic rod with-----negative--------charge.
Answer:
a) Since the height of the baseball at 99 m was 8.93 m and the fence at that distance is 3m tall, the hit was a home run.
b) The total distance traveled by the baseball was 108.7 m.
Explanation:
a) To know if the hit was a home run we need to calculate the height of the ball at 99 m:
![y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}](https://tex.z-dn.net/?f=%20y_%7Bf%7D%20%3D%20y_%7B0%7D%20%2B%20v_%7B0_%7By%7D%7Dt%20-%20%5Cfrac%7B1%7D%7B2%7Dgt%5E%7B2%7D%20)
Where:
: is the final height =?
: is the initial height = 1 m
: is the initial vertical velocity = v₀sin(45)
v₀: is the initial velocity = 32.5 m/s
g: is the gravity = 9.81 m/s²
t: is the time
First, we need to find the time by using the following equation:
![t = \frac{x}{v_{0_{x}}} = \frac{99 m}{32.5 m/s*cos(45)} = 4.31 s](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7Bx%7D%7Bv_%7B0_%7Bx%7D%7D%7D%20%3D%20%5Cfrac%7B99%20m%7D%7B32.5%20m%2Fs%2Acos%2845%29%7D%20%3D%204.31%20s)
Now, the height is:
Since the height of the baseball at 99 m was 8.93 m and the fence at that distance is 3m tall, the hit was a home run.
b) To find the distance traveled by the baseball first we need to find the time of flight:
![y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}](https://tex.z-dn.net/?f=%20y_%7Bf%7D%20%3D%20y_%7B0%7D%20%2B%20v_%7B0_%7By%7D%7Dt%20-%20%5Cfrac%7B1%7D%7B2%7Dgt%5E%7B2%7D%20)
![0 = 1 m + 32.5m/s*sin(45)t - \frac{1}{2}9.81 m/s^{2}t^{2}](https://tex.z-dn.net/?f=0%20%3D%201%20m%20%2B%2032.5m%2Fs%2Asin%2845%29t%20-%20%5Cfrac%7B1%7D%7B2%7D9.81%20m%2Fs%5E%7B2%7Dt%5E%7B2%7D)
![1 m + 32.5m/s*sin(45)t - \frac{1}{2}9.81 m/s^{2}t^{2} = 0](https://tex.z-dn.net/?f=1%20m%20%2B%2032.5m%2Fs%2Asin%2845%29t%20-%20%5Cfrac%7B1%7D%7B2%7D9.81%20m%2Fs%5E%7B2%7Dt%5E%7B2%7D%20%3D%200)
By solving the above quadratic equation we have:
t = 4.73 s
Finally, with that time we can find the distance traveled by the baseball:
![x = v_{0_{x}}*t = 32.5 m/s*cos(45)*4.73 s = 108.7 m](https://tex.z-dn.net/?f=%20x%20%3D%20v_%7B0_%7Bx%7D%7D%2At%20%3D%2032.5%20m%2Fs%2Acos%2845%29%2A4.73%20s%20%3D%20108.7%20m%20)
Hence, the total distance traveled by the baseball was 108.7 m.
I hope it helps you!
Answer:
Tires.
Explanation:
There are the few steps which are discussed below should be taken to increase or extend the life of tires.
(1) Avoid fast starts: Fast start of the vehicle will increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.
(2) Avoid fast stop: Fast stop of the vehicle will also increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.
(3) Avoid sharp turns: The alignment of the wheels and tires are in such a way that they work properly when vehicle is drive in a straight path but sharp turn will increase the uneven pressure on the tires will lead to decrease the life of tires.
Therefore, the life of tires can be extend by avoiding all the above mention actions such as fast stop, start and sharp turns.
Answer:
The net force on the block F(net) = mgsinθ).
Fw =mg(cosθ)(sinθ)
Explanation:
(a)
Here, m is the mass of the block, n is the normal force, \thetaθ is the wedge angle, and Fw is the force exerted by the wall on the wedge.
Since the block sliding down, the net force on the block is along the plane of the wedge that is equal to horizontal component of weight of the block.
F(net) = mgsinθ
The net force on the block F(net) = mgsinθ).
The direction of motion of the block is along the direction of net force acting on the block. Since there is no frictional force between the wedge and block, the only force acting on the block along the direction of motion is mgsinθ.
(b)
From the free body diagram, the normal force n is equal to mgcosθ .
n=mgcosθ
The horizontal component of normal force on the block is equal to force
Fw=n*sin(θ) that exerted by the wall on the wedge.
Substitute mgcosθ for n in the above equation;
Fw =mg(cosθ)(sinθ)
Since, there is no friction between the wedge and the wall, there is component force acting on the wall to restrict the motion of the wedge on the surface and that force is arises from the horizontal component for normal force on the block.