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RSB [31]
3 years ago
5

Four point masses, each of mass 1.9 $kg$ are placed at the corners of a square of side 2.2 $m$. Find the moment of inertia of th

is system about an axis that is perpendicular to the plane of the square and passes through one of the masses.

Physics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

I = 36.78 kg m^{2}

Explanation:\

Given data:

side of square = 2.2 m

mass =1.9 kg

The moment of inertia i is the total sum of the moments of inertia of the 4 point masses  and it is given as

I = I_1+I_2+I_3

= mr^{2} +mr^{2}+m(\sqrt2 r)^{2}

       = 2mr^{2}+2mr^{2}

         =4mr^{2}

       = 4*1.9*2.2^{2}

I = 36.78 kg m^{2}

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This question involves the concepts of density, volume, and mass.

The approximate diameter of a magnesium atom is "3.55 x 10⁻¹⁰ m".

<h3>STEP 1 (FINDING MASS OF INDIVIDUAL ATOM)</h3>

It is given that:

Mass of one mole = 24 grams

Mass of 6 x 10²³ atoms = 24 grams

Mass of 1 atom = \frac{24\ grams}{6\ x\ 10^{23}\ atoms} = 4 x 10⁻²³ grams

<h3>STEP 2 (FINDING VOLUME OF A SINGLE ATOM)</h3>

\rho = \frac{m}{V}\\\\V=\frac{m}{\rho}

where,

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Therefore,

V=\frac{4\ x\ 10^{-23}\ grams}{1.7\ grams/cm^3}

V = 2.35 x 10⁻²³ cm³

<h3>STEP 3 (FINDING DIAMETER OF ATOM)</h3>

The atom is in a spherical shape. Hence, its Volume can be given as follows:

V =\frac{\pi d^3}{6}\\\\d=\sqrt[3]{ \frac{6V}{\pi}}\\\\d=\sqrt[3]{ \frac{6(2.35\ x\ 10^{-23}\ cm^3)}{\pi}}

d = 0.355 x 10⁻⁷ cm = 3.55 x 10⁻¹⁰ m

Learn more about density here:

brainly.com/question/952755

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The answer is "60.74^{\circ}".

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Cavity and benzene should be extended in equal quantities.

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Answer:

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Explanation:

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