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RSB [31]
3 years ago
5

Four point masses, each of mass 1.9 $kg$ are placed at the corners of a square of side 2.2 $m$. Find the moment of inertia of th

is system about an axis that is perpendicular to the plane of the square and passes through one of the masses.

Physics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

I = 36.78 kg m^{2}

Explanation:\

Given data:

side of square = 2.2 m

mass =1.9 kg

The moment of inertia i is the total sum of the moments of inertia of the 4 point masses  and it is given as

I = I_1+I_2+I_3

= mr^{2} +mr^{2}+m(\sqrt2 r)^{2}

       = 2mr^{2}+2mr^{2}

         =4mr^{2}

       = 4*1.9*2.2^{2}

I = 36.78 kg m^{2}

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On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a 6 iron. The acceleration due to gravity on t
kozerog [31]

Answer:

a) 6 times farther.  b) 6 times longer.

Explanation:

Once released, in the horizontal direction, no other forces act on the ball, so it continues moving at the same initial velocity, which is given by the projection of the velocity vector in the horizontal direction, as follows:

vₓ = v* cos (25º) = 23 m/s * 0.906 = 20.8 m/s

In the vertical direction, the initial velocity is the projection of the velocity vector along the vertical axis, as follows:

vy = v* sin (25º) = 23 m/s * 0.422 = 9.72 m/s

Assuming that the acceleration is constant, and equal to 1/6*g, we can calculate the total time of flight, with the following kinematic equation for the vertical displacement:

y = voy*t - (\frac{1}{2}*\frac{g}{6} * t^{2} )

If the total displacement in the vertical direction is 0 (which means  that the time if the total time of flight), we can solve for t, as follows:

t = \frac{voy*12}{g} = \frac{9.72 m/s*12}{9.8m/s2} = 11. 9 s

On earth, this time could be calculated in the same way:

t = \frac{voy*12}{g} = \frac{9.72 m/s*2}{9.8m/s2} = 1.98 s

As the time is defined by the vertical movement, we can find the horizontal distance travelled on the moon, as follows:

Δx = v₀ₓ * t = 20.8 m/s * 11. 9 s = 248.1 m

On earth, the distance travelled had been as follows:

Δx = v₀ₓ * t = 20.8 m/s * 1.98 s = 41.3 m

⇒ Δx(moon) / Δx(earth) = 248.1 / 41.3 = 6.00

b) As we have just found, the time of flight on the moon and on the earth are as follows:

tmoon = 11. 9 s

tearth = 1.98 s

⇒ t(moon) / t(earth) = 11.9 / 1.98 = 6.0

8 0
3 years ago
The major contributions of Maury included:
scoray [572]
The best and most correct answer among the choices provided by your question is the second choice.

<span>The major contributions of Maury included mapping the ocean bottom.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
6 0
2 years ago
A. make an argument for halting the advances of technology? b. make an argument for continuing advances in technology
Naddik [55]
<span>Halting advances in tech could be useful because the automation in many tasks has rendered the human touch obsolete in many lower-level positions. They can be done by machines without the need for stoppage time for breaks. Continuing technology can be useful because it can increase output and make it easier for people to get what they're wanting or needing without spending extravagant amounts of resources.</span>
6 0
3 years ago
What is the instantaneous speed of the object after the five seconds?
OverLord2011 [107]

Answer:

12.5 m/s

Explanation:

In a acceleration time graph the area under the curve gives the change in velocity of the object. Here object starts at rest and therefore initial velocity is 0. After 5 seconds acceleration is 5m/s2.

change in velocity=area under the curve

change in velocity= 0.5*acceleration* change in time

v-0=0.5*5*5

v=12.5 m/s

7 0
3 years ago
Please help! I will give brainliest! Also can you please explain why it’s that answer. Thanks!
Veronika [31]

Answer:

B

Explanation:

Forces are pushes or pulls. They can be balanced or unbalanced. If unbalanced they can change the shape of objects and change the way they are moving (speed-wise)

5 0
3 years ago
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