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Alex Ar [27]
3 years ago
8

un futbolista patea una pelota que se encuentra en el pasto con un angulo de 30° (medido desde la horizontal) con la intención d

e hacer un gol en un arco que se encuentra a 30m desde su posición. si la altura del arco es de 2m (medido desde el pasto al travesaño) y el jugador patea directamente en dirección del arco, ¿a que velocidad debe patear la pelota para hacer el gol? ¿cuanto tiempo se demora la pelota en llegar al arco?
Physics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

i dont really know what it is

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Amy swims 500 m (0.5 km) in 6 minutes (0.1 hour ) . What was her speed in kilometers per hour ?
Scorpion4ik [409]
60 minutes = 1h
500/x = 10/100
She swam 5 kilometers per hour.
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2 years ago
The head of a grass string trimmer has 100 g of cord wound in a light, cylindrical spool with inside diameter 3.00 cm and outsid
faust18 [17]

Answer:

a).11.546J

b).2.957kW

Explanation:

Using Inertia and tangential velocity

a).

w=2250*2\pi *\frac{1}{60}\\ w=235.61

I=\frac{1}{2}*m*((\frac{d_{i} }{2})^{2} +(\frac{d_{e} }{2})^{2})\\m=100g *\frac{ikg}{1000g}=0.1kg\\ d_{i}=3cm*\frac{1m}{100cm}=0.03m \\ d_{e}=18cm*\frac{1m}{100cm}=0.18m\\I=\frac{1}{2}*0.1kg*((\frac{0.03m}{2})^{2} +(\frac{0.18m}{2})^{2})\\I=0.41625x10^{-3}kg*m^{2}

Now using Inertia an w

E=\frac{1}{2}*I*(w)^{2} \\ E=\frac{1}{2}*0.416x10^{-3}*(235.61)^{2} \\E=11.54J

average power=\frac{11.4J}{0.230s}=50.2 W

b).

power=t*w

P=11.5465*0.25*235.61

P=2.957 kW

4 0
3 years ago
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Answer:

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Explanation:

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Who was the first to hypothesize that electron orbit a positively charged nucleus
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6 0
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William Ferrel:
balu736 [363]

Answer:

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Explanation:

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3 years ago
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