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daser333 [38]
2 years ago
6

Estimate. Then find the difference 456,912 -37,800

Mathematics
1 answer:
wariber [46]2 years ago
7 0
The answer is 419,100 if you round to the hundreds place.
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Needed help with this question!
In-s [12.5K]
A) is 2x
b) is x^{3}
c) is -2x

I think these are correct.
log_{10}1000^{x] = log_{10}10^{2x}=2x
I did similar things to get other answers
1000^{log_{10}x} = 10^{3log_{10}x}=10^{log_{10}x^{3}}=x^{3}
5 0
3 years ago
Note: Figure is not drawn to scale.
zaharov [31]

The area of the object with a shape of kite having diagonals of 14 inches and 10 inches is 70 in².

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The area of kite = (product of diagonals)/2

Area of kite = (10 * 14) / 2 = 70 in²

The area of the object with a shape of kite having diagonals of 14 inches and 10 inches is 70 in².

Find out more on equation at: brainly.com/question/2972832

#SPJ1

6 0
2 years ago
Evaluate the following expression using the values given:
MrMuchimi
Replace each letter with it's value, so:
= (5*-2) + (-3*2) + 3
= -10 -6 +3
= -13
6 0
3 years ago
Read 2 more answers
Choose the answer based on the most efficient method as presented in the lesson.
natita [175]
The next step is to add 9

7 0
3 years ago
Read 2 more answers
A circle has been split into 8 sectors each of which can be colored as 4 different colors, and no consecutive sectors are colore
Eva8 [605]

Answer:

5832 ways

Step-by-step explanation:

Since the circle has 8 sectors and there is 4 colour,

Assuming the sectors are numbered 1 to 8,

Sector 1 : can be coloured with any of the 4 colour in 4 ways

Sector 2 can be coloured with any of the remaining 3 colours in 3 ways

Sector 3 in 3 ways without using the colour in sector 2

Sector 4 in 3 ways without using the colour in sector 3

Sector 5 in 3 ways without using the colour in sector 4

Sector 6 in 3 ways without using the colour in sector 5

Sector 7 in 3 ways without using the colour in sector 6

Sector 8 in 2 ways without using the colours in sector 1 and 7

Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways

3 0
2 years ago
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