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3 years ago

Please help! What is the value of X?

Mathematics

1 answer:

castortr0y [4]3 years ago

4 0

Angles are vertical opposite so they would be equal.
2x + 2 = 3x - 52
3x - 2x = 52 + 2
x = 54

In short, Your Answer would be 54

Hope this helps!

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Average of 2721 2557 2999 2278 4339

victus00 [196]

Answer:

Step-by-step explanation:

So we know that the average of numbers is all of the numbers added up and divided by the total amount of numbers.

2721

+ 2557

-------------------

5278

.... AND SO ON.........

=14,894 is all of the number added together!!!

Then we count up the numbers= 5

14,894/5

=2978.8

I hope this helps!!!

7 0

3 years ago

The number 42 is increased to 46. what is the percentage by which the number was increased?

Arte-miy333 [17]

Answer:

9.52% ( to 2 dec. places )

Step-by-step explanation:

Calculate the percentage increase using

percent increase = $\frac{increase}{original}$ × 100%

increase = 46 - 42 = 4, hence

percent increase = $\frac{4}{42}$ × 100% ≠ 9.52%

7 0

2 years ago

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

Learn more about equation solution from brainly.com/question/1679491

#learnwithBrainly

7 0

2 years ago

Is a proportional function f(x) = 5x linear? Why or why not? Explain with an example. k= 5/1

baherus [9]

Do you still need help with it I can help you?

5 0

2 years ago

Function P represents the perimeter, in inches, of a square with the side length x inches.

tatyana61 [14]

Answer:

x =0,1,2,3,4,5,6

P(x) =0,4,8,12,16,20,24

Step-by-step explanation:

P(x)= 4x

4 x 1 = 4

4 x 2 = 8

4 x 3 =12

4 x 4 = 16

4 x 5 = 20

4 x 6 = 24

7 0

3 years ago